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3 years ago

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1 answer:

xeze [42]3 years ago

3 0

Answer:

Transfer of electrons

Explanation:

GOOD LUCK FOR THE FUTURE! :)

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A closed cylindrical tank of radius 3.5 m and height 2m is made from

Dahasolnce [82]

Explanation:

Total surface area of cylinder:

$2\pi \times r(h + r) \\ 2 \times \pi \times 3.5(3.5 + 2) \\ 2\pi \times 19.25 = 120.951317 \\ 120.95 \: {cm}^{2}$

sheet of metal required = 120.95 cm^2

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3 years ago

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I will make brainliest! PLS HELPPP!!

inysia [295]

Answer:

1.A compound is when two substances are put together and there is a reaction creating a new substance Ex. H20. A mixture is when two substances are put together, there is no reaction and they can be separated easier than compounds. Ex. salad dressing.

2.Atomic bonds

3.Compound

4.Element

5.Mixture

Explanation:

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3 years ago

What work is done by a system on its environment when an ideal gas is maintained at a constant pressure of 200 newtons/meter2 du

Crank

<u>Answer:</u>

Work done done by a system on its environment is W=40 Joules

<u>Explanation:</u>

<u>Given:</u>

Ideal gas is maintained at a constant pressure $P=200 \frac{N}{m^{2}}$

Change in Volume $d v= -0.2 m^{3}$

<u>To find:</u>

Work done by a system during an Isobaric Process

<u>Solution:</u>

In a Isobaric Process, constant pressure is maintained, $P=200 \frac{N}{m^{2}}$

According to the formula,

work done $\bold{W=P \times d v}$

Substitute the values of pressure and change in volume in the above formula,

$=200 \times -0.2$

$=40 \text { Joules }$

<u>Result:</u>

Work done done by a system W= -40 Joules

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3 years ago

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Find electric field at point p which is a distance l away from the both +q and -q

denis-greek [22]

Answer:

$\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }$

Explanation:

As given point p is equidistant from both the charges

It must be in the middle of both the charges

Assuming all 3 points lie on the same line

Electric Field due a charge q at a point ,distance r away

$=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{r^{2} }$

Where

q is the charge
r is the distance
$E$ is the permittivity of medium

Let electric field due to charge q be F1 and -q be F2

I is the distance of P from q and also from charge -q

⇒

F1 $=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }$

F2 $=\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }$

⇒

F1+F2= $\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }$

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4 years ago

Population I stars are found in what area of the Milky Way?

nekit [7.7K]

Spiral Arms is the definite answer

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3 years ago

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