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3 years ago

How do u charge ur phone? :)

2 answers:

8 0

So what you do is, you grab your charger and then after that you plug it into the wall, and then plug the smaller part into your phone :)

Pepsi [2]3 years ago

7 0

With a phone charger.

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If the open circuit voltage of a circuit containing ideal sources and resistors is measured at 6 V, while the current through th

Trava [24]

Given Information:

Current of Ideal source = Is = 100 mA = 0.100 A

Open circuit voltage = Voc = 6 V

Short circuit current = Isc = 200 mA = 0.200 A

Required Information:

Power absorbed by idea current source = ?

Answer:

Power absorbed by idea current source = 0.3 Watts

Explanation:

Ideal Current Source:

An ideal current source doesn't have internal resistance and provides constant current regardless of the voltage supplied to the circuit.

The power absorbed by the ideal source can be found using

P = Is²R

Where Is is the ideal source current and R can be found using

R = Voc/Isc

Where Voc is the open circuit voltage and Isc is the short circuit current.

R = 6/0.200

R = 30 Ω

Therefore, the power absorbed by the ideal current source is

P = Is²R

P = (0.100)²*30

P = 0.3 Watts

7 0

3 years ago

PLEASE HELPPPPPPP!!!!,

raketka [301]

software engineers

hardware engineers

metallurgic engineers

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4 0

3 years ago

Read 2 more answers

Automobiles must be able to sustain a frontal impact. Specifically, the design must allow low speed impacts with little damage,

Naya [18.7K]

Answer:

Explanation:

The concept of Hooke's law was applied as it relates to deformation.

The detailed steps and appropriate substitution is as shown in the attached file.

8 0

3 years ago

External crack of length of 3.0 mm was detected on the surface of the shaft of wind turbine made from 4340 steel. The diameter o

sveticcg [70]

Answer:

The correct answer is " $K_c=6.0369 \ MPa\sqrt{m}$ ".

Explanation:

Given:

Maximum load,

P = 50,000 N

Crack length,

a = 3mm

or,

= 3×10⁻³ m

Diameter,

d = 32 mm

As we know,

⇒ Maximum stress, $\sigma=\frac{P}{A}$

$=\frac{50000}{(\frac{\pi}{4}\times 32^2)}$

$=62.20 \ N/mm^2$

Now,

⇒ Fracture tougness, $K_c=Y \sigma\sqrt{\pi a}$

On substituting the values, we get

$=1\times 62.20\times \sqrt{3.14\times 3\times 10^{-3}}$

$=6.0369 \ MPa\sqrt{m}$

4 0

3 years ago

Serratia marcescens bacteria are used for the production of threonine. The maximum specific oxygen uptake rate of S. marcescens

Sati [7]

Answer:

The rate of cell metabolism is limited by mass transfer since the value of maximum cell concentration obtained (38 g/l) is lower than 50 g l-1, the value planed.

Explanation:

Data

kLa = 0.17/s

Solubility of oxygen = 8 × 10^-3 kg / m^3

The maximum specific oxygen uptake rate = 4 mmol O2 / g h.

Concentration of oxygen = 0.5 × 10^-3 kg/ m^3

**The maximum cell density = 50 g/l

___________________

The calculated maximum cell concentration:

xmax= kLa · CAL*/ qo

CAL* is the solubility of oxygen in the broth and qo is the specific oxygen uptake rate

Replacing the data given

xmax= ( 0.17/s ) · (8 × 10^-3 kg / m^3) / 4 mmol O2 / g h

4 mmol O2 / g h to kg O2/ g s

$4 \frac{mmol}{gh} \frac{1 gmol}{1000mmol}\frac{1h}{3600s}\frac{32 g}{gmol} \frac{1Kg}{1000g}$

= 3.56 x 10^-3 kg O2/ g s

So then,

xmax= ( 0.17/s ) · (8 × 10^-3 kg / m^3) / 3.56 x 10^-3 o kg O2/ g s

xmax= 3. 8 x 10^4 g/ m^3 = 38 g/l

_____________________

5 0

3 years ago