The reaction will shift toward the products.
Adding more reactant will shift the reaction to the product.
Answer:
single orbital, s sub level.
three orbitals, p sub level
5 orbitals , d sub level
seven orbital , f sub level
Answer:
the % yield is 82%
Explanation:
Given the data in the question,
we know that;
Molar mass of benzil is 210.23 g·mol−1
Molar mass of dibenzyl ketone is 210.27 g·mol−1
Molar mass of tetraphenylcyclopentadienone is 384.5 g·mol−1
Now,
2.0 g benzil = 2 g / 210.23 g·mol−1 = 0.0095 mole
2.2 g dibenzyl ketone = 2.2 / 210.27 = 0.0105 mole
3.0 g of tetraphenylcyclopentadienone = 3 / 384.5 = 0.0078 mole
Now, the limiting reagent is benzil. 0.0095 mole can reacts wiyh 0.0095 mole of dibenzyl ketone
percentage yield = ( 0.0078 mole / 0.0095 mole ) × 100%
= 0.82 × 100%
= 82%
Therefore, the % yield is 82%
Answer:
HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)
Explanation:
Aqueous solution of HCl and aqueous solution of KOH react as follow:
HCl(aq) + KOH(aq) —>
In solution, HCl and KOH will dissociates as follow:
HCl —> H+ + Cl-
KOH —> K+ + OH-
During the reaction, a double displacement reaction occur as shown below:
H+ + Cl- + K+ + OH- —> K+Cl- + H+OH-
The elemental equation is given below:
HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)
