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iogann1982 [59]
11 months ago
7

In each part calculate the kinetic energy of the given objects in joules a) an automobile whose mass is 1260kg moving at a speed

of 66.3km/h b) a runner whose mass is 64.7 kg, moving at a speed of 8.52m/s c) an electron (mass 9.11x10^31kg) moving at a speed of 2.74x10^7m/s
Physics
1 answer:
Contact [7]11 months ago
5 0

a)

Kinetic energy (KE) = 1/2 m v^2

Where:

m = mass = 1260 kg

v = speed = 66.3 km/h = 18.42 m/s

Replacing:

KE = 1/2 (1260 kg ) (18.42 m/s )^2 = 213,756.7 J

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Answer:

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d) 140 N

c) 1) Increasing the brake fluid  pressure

2)  Increasing the slave piston surface area.

Explanation:

The parameters given are;

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Cross sectional area of the master cylinder piston = 8 cm² = 8 × 10⁻⁴ m²

The pressure P on the brake fluid is given by the formula for pressure as follows;

P= \dfrac{Applied \ force}{Area \over \ which \  force \ is \ applied} = \dfrac{28 \, N}{8 \times 10^{-4} \, m^2} = 35,000 \, N/m^2 = 35,000 \, Pa

The pressure on the brake fluid, P, produced by the master cylinder piston = 35,000 Pa = 35 kPa

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P= \dfrac{Applied \ force}{Area \over \ which \  force \ is \ applied} = \dfrac{Applied \ force}{4 \times 10^{-3} \, m^2} = 35,000 \, N/m^2

Therefore;

Applied force on the slave piston = 4 × 10⁻³ m² × 35,000 N/m² = 140 N

c) The force, F produced by the slave cylinder piston is given by the relation;

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Therefore, the two ways of increasing the force produced by the slave cylinder piston is as follows;

1) Increasing the pressure in the brake fluid by increasing the force exerted by the master cylinder piston

2) Increasing the surface area of the slave piston.

4 0
3 years ago
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