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zaharov [31]
2 years ago
9

What is the most likely outcome? it will become a permanent magnet because the domains will remain aligned. it will become a tem

porary magnet because the domains will remain aligned. it will become a permanent magnet because the domains will easily realign. it will become a temporary magnet because the domains will easily realign.
Physics
1 answer:
erma4kov [3.2K]2 years ago
4 0

The likely outcome when a magnetically soft material is placed in a strong magnetic field is that it will become a temporary magnet because the domains will easily realign.

<h3>What is a magnet?</h3>

A magnet is a material whose magnetic domains are properly aligned. These materials are able to attract other materials that are magnetizable.

Hence, the likely outcome when a magnetically soft material is placed in a strong magnetic field is that it will become a temporary magnet because the domains will easily realign.

Missing parts:

A magnetically soft material is placed in a strong magnetic field. What is the most likely outcome?

a. It will become a permanent magnet because the domains will remain aligned.

b. It will become a temporary magnet because the domains will remain aligned.

c. It will become a permanent magnet because the domains will easily realign.

d. It will become a temporary magnet because the domains will easily realign.

Learn more about magnets:brainly.com/question/14301573

#SPJ1

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If two particles have equal kinetic energies, are their momenta necessarily equal? explain.
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Answer:

No the given statement is not necessarily true.

Explanation:

We know that the kinetic energy of a particle of mass 'm' moving with velocity 'v' is given by

K.E=\frac{1}{2}mv^{2}

Similarly the momentum is given by m\times v

For 2 particles with masses m_{1},m_{2}and moving with velocities v_{1},v_{2} respectively the respective kinetic energies is given by

K.E_{1}=\frac{1}{2}m_{1}v_{1}^{2}

K.E_{2}=\frac{1}{2}m_{2}v_{2}^{2}

Similarly For 2 particles with masses m_{1},m_{2}and moving with velocities v_{1},v_{2} respectively the respective momenta are given by

p_{1}=m_{1}\times v_{1}

p_{2}=m_{2}\times v_{2}

Now since it is given that the two kinetic energies are equal thus we have

\frac{1}{2}m_{1}v_{1}^{2}=\frac{1}{2}m_{2}v_{2}^{2}\\\\(m_{1}v_{1})\times v_{1}=(m_{2}v_{2})\times v_{2}\\\\p_{1}\times v_{1}=p_{2}\times v_{2}\\\\\therefore \frac{p_{1}}{p_{2}}=\frac{v_{2}}{v_{1}}............(i)

Thus we infer that the moumenta are not equal since the ratio on right of 'i' is not 1 , and can be 1 only if the velocities of the 2 particles are equal which becomes a special case and not a general case.

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Q) A farmer moves along the boundary of a
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What is the speed of a wave if the wavelength is 100m and the period is 20s
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3.7. A dog searching for a bone walks 3.50 m south, then 8.20 m at an angle 23.1 degrees north of east, and finally 15.0 m west.
andriy [413]

Answer:

Explanation:

We shall represent displacement of dog in vector form , in terms of i , j , i representing east  and  j representing north .

Dog travels 3.5 m south .

Displacement D₁ = - 3.5 j

then dog travels 8.2 m , 23.1 degree north of east

Displacement D₂ = 8.2 cos23.1 i + 8.2 sin23 j

D₂ = 8.2 cos23.1 i + 8.2 sin23.1  j

= 7.54 i + 3.22 j  

Third displacement

D₃ = - 15i

Total displacement = D₁ + D₂ + D₃

= - 3.5 j + 7.54 i + 3.22 j  -15i

= - 7.46 i - 0.28 j

Magnitude of displacement = √ ( 7.46² + .28²)

= √(55.65 + .08 )

= 7.46 m

b ) Direction of displacement

If Ф be angle , displacement makes with west direction

TanФ =  .08 / 55.65 = .00143

Ф = .082 degree south of west or almost west .

From east , this angle = 180 + .082 = 180.082 , counterclockwise .

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3 years ago
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