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Advocard [28]
3 years ago
12

Give 2 examples of force pairs that occur when you clean your room?

Chemistry
1 answer:
KATRIN_1 [288]3 years ago
4 0
On eof the forces is inertia. This can happen when you move your furniture to clean under them. When you move an object in a straight line without chanign its composition (e.g moving a chair or a table from one side to the other) you are working with inertia. The secon force is friction. It s present when you clean a surface by rubbing it with a tool like a damp cloth or a mop. 
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A scientist carries out an experiment how could she help other scientists judge the validity
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Logging her results of change day-by-day in a scientific journal. As well as provide as much evidence as possible to support her claim.
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56. What would be the valence electrons of 14Si, 16S, 32Ge respectively?
Leokris [45]

Answer: D. 4,6,4

Explanation:

The valence electron is the electron found in the outermost shell of an atom, and participates in bond formation.

For the following element, the valence electron can be noticed when we write the electronic configuration of each element.

Silicon =  1s2 2s2 2P6 3s2 3p2

Sulphur = 1s2 2s2 2P6 3s2 3p4

Germanium =  1s2 2s2 2P6 3s2 3p6 3d10 4s2 4p2

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3 years ago
Oxidation-reduction is often the most confusing and abstract part of chemistry for first-time chemistry students. Is it really w
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3 years ago
Given the reaction: 4Na + O2 → 2Na2O How many moles of oxygen are completely consumed in the production of 1.00 mole of Na2O?
Levart [38]
The answer is 0.5 moles because if 1 moles of o2 is consumed to produce 2 moles of Na2O, then 0.5 moles of o2 will be consumed to produce 1 mole of Na2O.<span />
4 0
3 years ago
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The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) ⇌ 2NO(g) Kc = 4.3 ×
Anuta_ua [19.1K]

Answer:

Kc=~1.49x10^3^4}

Explanation:

We have the reactions:

A: N_2_(_g_) + O_2_(_g_)  2NO_(_g_)~~~~~~Kc = 4.3x10^-^2^5

B: 2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~~~Kc = 6.4x10^9

Our <u>target reaction</u> is:

4NO_(_g_)  N_2_(_g_) + 2NO_2_(_g_)

We have NO_(_g_) as a reactive in the target reaction and  NO_(_g_) is present in A reaction but in the products side. So we have to<u> flip reaction A</u>.

A: 2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}

Then if we add reactions A and B we can obtain the target reaction, so:

A: 2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}

B: 2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~Kc=6.4x10^9

For the <u>final Kc value</u>, we have to keep in mind that when we have to <u>add chemical reactions</u> the total Kc value would be the <u>multiplication</u> of the Kc values in the previous reactions.

4NO_(_g_)  N_2_(_g_) + 2NO_2_(_g_)~~~Kc=\frac{6.4x10^9}{4.3x10^-^2^5}

Kc=~1.49x10^+^3^4}

3 0
3 years ago
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