Answer:
0.023 mol/(L*s).
Explanation:
Equation of the reaction:
2 D(g) + 3 E(g) + F(g) => 2 G(g) + H(g)
Using stoichiometry, 2 moles of D reacts with 3 moles of E and 1 mole of F to give the above products.
1 mole of D will react with 3/2 moles of E.
Delta[D]/delta t = 0.15 mol/L.s
Delta[E]/delta t = (3/2) * 0.15 =
= 0.023 mol/(L*s).
CHEBI:43098 - heptane
A straight-chain alkane with seven carbon atoms. It has been found in Jeffrey pine (Pinus jeffreyi). Heptane or n-heptane is the straight-chain alkane with the chemical formula H3C(CH2)5CH3 or C7H16, and is one of the main components of gasoline (petrol)
Molecular weight of CS2 = 76.14 g
number of moles of CS2 =
=
= 1.773
Now, 1.733 mol requires 43.2 kj of heat to vaporize.
∴ 1 mol will require
= 24.4 kj/mol
Thus, correct answer is option B
The items are answered below and are numbered separately for each compound.
The freezing point of impure solution is calculated through the equation,
Tf = Tfw - (Kf)(m)
where Tf is the freezing point, Tfw is the freezing point of water, Kf is the freezing point constant and m is the molality. For water, Kf is equal to 1.86°C/m. In this regard, it is assumed that m as the unit of 0.25 is molarity.
1. NH4NO3
Tf = 0°C - (1.86°C/m)(0.25 M)(2) = -0.93°C
2. NiCl3
Tf = 0°C - (1.86°C/m)(0.25 M)(4) = -1.86°C
3. Al2(SO4)3
Tf = 0°C - (1.86 °C/m)(0.25 M)(5) = -2.325°C
For boiling points,
Tb = Tbw + (Kb)(m)
For water, Kb is equal to 0.51°C/m.
1. NH4NO3
Tb = 100°C + (0.51°C/m)(0.25 M)(2) = 100.255°C
2. NiCl3
Tb = 100°C + (0.51°C/m)(0.25 M)(4) = 100.51°C
3. Al2(SO4)3
Tb = 100°C + (0.51°C/m)(0.25 M)(5) = 100.6375°C
One thing incorrect is that when dealing with a compound, such as H2SO4, that has 7 atoms in the chemical formula, the polyatomic ion SO4 doesn’t dissociate into one Sulfur and four Oxygens. SO4 stays and a PAI.
