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3 years ago

Help please!!! 100 points

Physics

2 answers:

NeX [460]3 years ago

8 0

1. Acceleration
2. If you are going 12 meters per second and you want to know how many seconds it takes yo get to 105 meters, you need yo find how long it takes to go horizontally then vertically. 12 seconds.
3. B

Nastasia [14]3 years ago

5 0

1. baseball in air w/ no force but only gravity acting on it. gravity is constant so its acceleration is constant. ans is A.

2. use the eqn s=u*t+1/2a*t^2 where u=init vel n a=accel

s=105m,

u=0 as the rock has no vertical vel

n a=gravity=9.8m/s^2

105=0*t+1/2*9.8*t^2

t^2~23

t~5s

ans is A.

3. same eqn s=u*t+1/2a*t^2 where u=init vel n a=accel

s=1.4m,

u=0 as the marble has no vertical vel

n a=gravity=9.8m/s^2

1.4=0*t+1/2*9.8*t^2

t^2=2.8/9.8=0.2857

t=0.5345s

V=4/0.5345=7.48m/s

ans is C

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A. subjective well-being

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3 years ago

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Novay_Z [31]

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2 years ago

A girl takes her dog for a walk on a sunny beach. Find the force of gravity between the 45-kg girl and her 11-kg dog when they a

Lady_Fox [76]

The gravitational force acting between them is $8.25*10^-^9N$

Data given;

M1 = 45kg
M2 = 11kg
r = 2.0m
G = $6.67*10^-^1^1m^3kg^-^1s^-^1$

To solve this question, we need to apply gravitational force or energy formula.

<h3>Gravitational Force</h3>

This states that the force of attraction between two bodies is equal to the product of their bodies and inversely proportional to the square of their distance apart.

Mathematically;

$F = \frac{GM_1M_2}{r^2} \\$

let's substitute the values and solve

$F = \frac{Gm_1m_2}{r^2}\\F = \frac{6.67*10^-^1^1 * 45 * 11}{2^2}\\F = 8.25*10^-^9N$

The force of gravity acting between them is $8.25*10^-^9N$

Learn more on gravitational force here;

brainly.com/question/11359658

4 0

3 years ago

For a wave, what term is defined as the maximum height of a crest, or depth of a trough, relative to the normal level? for a wav

sammy [17]

The appropriate response is amplitude. Amplitude is the target estimation of the level of progress (positive or negative) in environmental weight (the pressure and rarefaction of air atoms) created by sound waves.

I hope the answer will help you.

6 0

3 years ago

13.An airplane starts from rest at the end of a runway and accelerates at a constant rate. In the first second, the airplane tra

Murrr4er [49]

Answer:

The answer is 3.33m

Explanation:

The acceleration "a" is constant.

Acceleration is the variation of velocity over time,

$\frac{dv}{dt} = a$ .

solving the last equation

$\int_{v_0}^v dv = a\int_0^t dt \rightarrow v-v_0 = at$ ,

where $v_0=0$ because the airplane starts from rest.

Once again, velocity is the variation of distance over time.

$\frac{dx}{dt} = at \rightarrow \int_{x_0}^x dx = a\int_0^t t\ dt$

then

$x- x_0 = \frac{1}{2}at^2$

where $x_0=0$ if we consider the end of the runway as the initial point (this step is for simplicity but you can let it expressed, it's going to cancel anyway).

If $x=1.11\ m$ at $t=1s$ , then

$a = \frac{2x}{t^2} = 2.22\ m/s^2$

and the final expression for the distance is

$x = 1.11 t^2$ .

If t = 2s, x = 4.44 m. Which means thad the additional distance is

$x(2s) - x(1s) = 4.44 - 1.11 = 3.33\ m$

8 0

4 years ago