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Ksju [112]
3 years ago
7

How many kilograms of potassium iodide (ki) are needed to make 1.25 l of a 4.41 m ki solution?

Chemistry
1 answer:
Lapatulllka [165]3 years ago
7 0
C = n/V
n = C×V
n = 4,41M × 1,25L
n = 5,5125 mol

mKI: 39+127 = 166 g/mol

1 mol --------- 166g
5,5125 mol --- X
X = 166×5,5125 = 915,075g KI

:)
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Answer:

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Explanation:

First of all, think the reaction:

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3 years ago
How many miles are there in 20g of KClO3 (k=39 Cl=35.5 O=16)​
SashulF [63]
<h3>Answer:</h3>

0.144 moles

<h3>Explanation:</h3>
  • The relationship between mass of a compound, number of moles and molar mass of the compound is given by;
  • Number of moles = Mass ÷ Molar mass
  • Molar mass is equivalent to the relative formula mass of the compound that is calculated the atomic masses of the elements making the compound.

In this case;

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Therefore;

Number of moles = 20 g ÷ 138.5 g/mol

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Sorry if I'm wrong but I think that it is B. 
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