The number of particles= 1.43 x 10²⁴ particles
<h3>Further explanation</h3>
Given
53.2 L volume of gas at STP
Required
The number of particles
Solution
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.
So mol for 53.2 L :
= 53.2/22.4
= 2.375 moles
1 mol = 6.02 x 10²³ particles (molecules, atoms, ions)
The number of paricles for 2.375 moles gas :
= 2.375 x 6.02 x 10²³
= 1.43 x 10²⁴ particles
do you mean fractional distillation of crude oil ?
if you do then this is what happens:
basically, crude oil is made up of a lot of hydrocarbons so it's put into a fracitonating column to separate these compounds into fractions. the top of the fractionating column is colder whereas the bottom of the column is hotter.
gases, petrol, diesel and kerosene come out near the top of the top of the column because they are shorter chains. substances near the top of the column also have a lower boiling point (since it's cooler and there's less intermolecular forces).
the substances at the top of the column are typically useful fuels because they have a higher ease of ignition (higher up=easier to ignite, lower down = harder to ignite). Also, substances at the top have a low viscosity so they can flow easily.
substances that come out near the bottom of the fracitonating column include fuel oil and bitumen.
these are longer chains of hydrocarbons and bitumen is used for road surfacing.
these substances have a high viscosity (harder to flow) and have a high boiling point since they have more intermolecular forces which require a lot of energy to break. Also the bottom of the fractionating column is warmer and this is where these fractions are released.
Answer:
144.12873
Explanation:
Hope this helps you
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回答:
144.12873
説明:
これがお役に立てば幸いです
The solubility of KCl in boiling water is 56.3 g / 100 g water So each gram of water dissolve 56.3 / 100 = 0.563 g KCl in g water
We have here 50 g water so the total amount of KCl dissolved = 50 * 0.563 = 28.15 g KCl
We have 250 g KCl so it is not dissolved completely (only 28.15 g KCl will be dissolved)