They would have used a total of 30 horses. Each person would've each ridden 15 so 15+15= 30 and 165 divided by 11 is 15. Hope this is off help!
5d - 7 = -13
5d = -13 + 7
5d = -6
d = -6/5
Answer:

Step-by-step explanation:
<u>Properties of Logarithms</u>
We'll recall below the basic properties of logarithms:

Logarithm of the base:

Product rule:

Division rule:

Power rule:

Change of base:

Simplifying logarithms often requires the application of one or more of the above properties.
Simplify

Factoring
.

Applying the power rule:

Since


Applying the power rule:

Applying the logarithm of the base:

Answer:
Arithmetic Sequence
Step-by-step explanation:
we know that
In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, and this constant is called the common difference
we have

Let




so
the difference between one term and the next is a constant
The common difference is equal to 1
This is an Arithmetic Sequence