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astraxan [27]
3 years ago
14

Describe how mixtures relate to substances

Chemistry
1 answer:
Svetach [21]3 years ago
8 0
All Matter can be Classified into two Categories pure substances and mixtures a pure substance consists of a single element or compound a mixture however is made up of differ
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OHC-CH2-CH2-CH2-CHO<br><br> What is the IUPAC name of this compound ?
Rufina [12.5K]

Answer:

Pentan_1,5_di-al

Explanation:

OHC-CH₂-CH₂-CH₂-CHO

This is Pentan_1,5_di-al

If we break this compound, we will observe that there is presence aldehyde group and hence the functional group "al". This aldehyde is bonded to carbon 1 and carbon 5 respectively.

Also the pentan is due to presence of 5 carbon atoms.

Therefore, the IUPAC name of this compound (OHC-CH₂-CH₂-CH₂-CHO) is  Pentan_1,5_di-al

5 0
3 years ago
A person loses 2.70 lb in two weeks. how many grams did they lose?
leonid [27]

Answer:

1224.7

Explanation:

Each lb is 453.59

6 0
3 years ago
A student does an experiment to determine the molar solubility of lead(II) bromide. She constructs a voltaic cell at 298 K consi
attashe74 [19]

Answer:

The molar solubility of lead bromide at 298K is 0.010 mol/L.

Explanation:

In order to solve this problem, we need to use the Nernst Equaiton:

E = E^{o} - \frac{0.0591}{n} log\frac{[ox]}{[red]}

E is the cell potential at a certain instant, E⁰ is the cell potential, n is the number of electrons involved in the redox reaction, [ox] is the concentration of the oxidated specie and [red] is the concentration of the reduced specie.

At equilibrium, E = 0, therefore:

E^{o}  = \frac{0.0591}{n} log \frac{[ox]}{[red]} \\\\log \frac{[ox]}{[red]} = \frac{nE^{o} }{0.0591} \\\\log[red] =  log[ox] -  \frac{nE^{o} }{0.0591}\\\\[red] = 10^{ log[ox] -  \frac{nE^{o} }{0.0591}} \\\\[red] = 10^{ log0.733 -  \frac{2x5.45x10^{-2}  }{0.0591}}\\\\

[red] = 0.010 M

The reduction will happen in the anode, therefore, the concentration of the reduced specie is equivalent to the molar solubility of lead bromide.

7 0
3 years ago
What is 0.045 rounded to the nearest hundredth?
deff fn [24]
0.05 is the answer to your question
5 0
3 years ago
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18.The average or small size stars become a _________ at the end of their life cycle.
wel
The answer is B, Neutron star
5 0
3 years ago
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