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irinina [24]
3 years ago
14

In the circuit diagram what does the line segment with two circles at the ends represent?

Chemistry
1 answer:
telo118 [61]3 years ago
4 0
I believe it would be a open switch because it is not connected to anything.
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Compare and contrast the use of U-238 and C-14 in absolute age dating
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Carbon-14 and Uranium-238 have something we call a half live, which is basically a known time period for it to change half of its C-14 or U-238 radioactively decay. Since we know how long that is 5730 years for Carbon-14 for half a sample to deteriorate, than we can figure out how old it is.



7 0
4 years ago
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The radius of a hydrogen atom is 37 pm and its mass is 1.67 × 10-24 g. What is the density of the atom in grams per cubic centim
RoseWind [281]

Answer:

V = 4/3 * 3.1416 * (37x10-10)3

V = 2.12x10-25 cm3

d = m/V

d = 1.67x10-24 / 2.12x10-25 = 7.87 g/cm3

The difference in temperature, let's convert F to ºC:

ºC = -80-32/1.8 = -62.22 ºC

dT = -92.6 + 62.2 = -30.4 ºC

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4 years ago
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Theoretical<br> Yield of Cu<br> based on<br> Amount of CuSO4
fiasKO [112]

Answer:

I hope this helps.

Explanation:

6 0
3 years ago
Please help me!!!!!!
Norma-Jean [14]

Answer:

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4 0
3 years ago
There are three naturally occurring isotopes of the hypothetical element hilarium 45Hi, 46Hi, and 48Hi. The percentages of these
den301095 [7]

Answer:

46.761g/mol

Explanation:

Given parameters:

Element = Hilarium , Hi

Isotopes: Hi- 45, Hi-46 and Hi- 48

Natural abundance of Hi-45 = 18.3%

                                     Hi-46 = 34.5%

                                     Hi-48 = 47.2%

Unknown:

Atomic weight of naturally occurring Hilarium = ?

Solution:

Isotopes have been studied extensively by mass spectrometry. The method is used to determine the proportion/percentage/fraction by which each of the isotopes of an element occurs in nature. The proportion is called geonormal abundance. From this we can calculate the atomic weight of an element.

 We can use the expression below to find this value:

       Atomic weight = m₄₅α₄₅ + m₄₆α₄₆ + m₄₈α₄₈

    m is the atomic mass of each isotope and α is the abundance

Atomic weight = (45 x \frac{18.3}{100} ) + (46 x  \frac{34.5}{100} ) + (48 x  \frac{47.2}{100})

Atomic weight of Hi = 8.235 + 15.870 +  22.656 = 46.761g/mol

6 0
3 years ago
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