The area is 60.2, to find area it's length times width.
I would say C is the most correct.
In D it depends on what water source you're using. Let's say it is a waterfall, then the source of the water (melting ice or a lake) may disappear in the future.
If you're using underwater "windmills" placed in the ocean, then you would expect it to last a while as the ocean will not disappear in the near future.
[Ar] 3d10 4s2 4p5 is the electron configuration of bromine
Answer:
44 grams/mole
Explanation:
<u>If 1 mol of XO₂ contains the same number of atoms as 60 g of XO3, what is the molar mass of XO₂?</u>
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60 grams of XO3 is one mole XO3, since it has the same number of atoms as 1 mole of XO2.
Let c be the molar mass of X. The molar mass of XO3 is comprised of:
X: c
3O: 3 x 16 = 48
Total molar mass of XO3 is = <u>48 + c</u>
We know that the molar mass of XO3 = 60 g/mole, so:
48 + c = 60 g/mole
c = 12 g/mole
The molar mass of XO2 would be:
1 X = 12
2 O = 32
Molar mass = 44 grams/mole, same as carbon dioxide. Carbon's molar mass is 12 grams.
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Answer : The value of equilibrium constant for this reaction at 262.0 K is 
Explanation :
As we know that,
where,
= standard Gibbs free energy = ?
= standard enthalpy = -45.6 kJ = -45600 J
= standard entropy = -125.7 J/K
T = temperature of reaction = 262.0 K
Now put all the given values in the above formula, we get:
The relation between the equilibrium constant and standard Gibbs free energy is:
where,
= standard Gibbs free energy = -12666.6 J
R = gas constant = 8.314 J/K.mol
T = temperature = 262.0 K
K = equilibrium constant = ?
Now put all the given values in the above formula, we get:
Therefore, the value of equilibrium constant for this reaction at 262.0 K is
