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3 years ago

How many grams of potassium iodide will produce 500 grams of silver iodide, when there is an excess of silver nitrate?Why?

Chemistry

1 answer:

nevsk [136]3 years ago

7 0

Answer:

None of the options are correct. The answer to the question is 353.2g

Explanation:

The equation for the reaction between is given below:

KI + AgNO3 —> KNO3 + AgI

Molar Mass of KI = 39 + 127 = 166g/mol

Molar Mass of AgI = 108 + 127 = 235g/mol

From the equation,

166g of KI produced 235g of AgI.

Therefore, Xg of KI will produce 500g of AgI i.e

Xg of KI = (166 x 500)/235 = 353.2g

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3 years ago

2) which statement describes ionic bonding?

garik1379 [7]

Answer

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