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Shalnov [3]
3 years ago
13

A mother (mass 60.0 kg) skates across an ice rink with negligible friction toward her child (mass 20.0 kg), who is standing stil

l on the ice. If the mother moves at 4.0 m/s before she picks up her child, what is her new speed after she picks up her child and holds onto him
Physics
1 answer:
Lyrx [107]3 years ago
7 0

We have that the new speed after she picks up her child is mathematically given as

V2=3m/s

<h3>Speed</h3>

The speed of a body is simply the rate at which the body moves or functions, the speed of a body is measured with an SI unit of m/s.

Generally the equation for the  Velocity is mathematically given as

m1v1=m2v2

Therefore

v2=\frac{60*4}{60+20}

V2=3m/s

For more information on Speed

brainly.com/question/7359669

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The core of a star must be at the temperature of 10,000,000 degrees Celsius for hydrogen fusion to begin. 
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Please help giving 15 points<br> How do you calculate the density of an object?
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A solid disk of mass 2 kg and radius 2 m is given a horizontal push of 20N at a point .3 m above its center. a. What is the mini
Margaret [11]

Answer:

\mu_s=1.0205

Explanation:

Given:

  • mass of solid disk, m=2\ kg
  • radius of disk, r=2\ m
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  • distance of application of force from the center, s=0.3\ m

<em>For the condition of no slip the force of  static friction must be greater than the applied force so that there is no skidding between the contact surfaces at the contact point.</em>

\therefore F

where:

f_s = static frictional force

\Rightarrow 20

\Rightarrow 20

\Rightarrow 20

\mu_s>1.0204

7 0
3 years ago
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As such, all objects free fall at the same rate regardless of their mass. Because the 9.8 N/kg gravitational field at Earth's surface causes a 9.8 m/s/s acceleration of any object placed there, we often call this ratio the acceleration of gravity.

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When objects fall to the ground, gravity causes them to accelerate. Acceleration is a change in velocity, and velocity, in turn, is a measure of the speed and direction of motion. Gravity causes an object to fall toward the ground at a faster and faster velocity the longer the object falls.

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5 0
2 years ago
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A ship 1200m off shore fires a gun. how long after the gun is fired will it be heard on the shore?​
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Answer:

We know that the speed of sound is 343 m/s in air

we are also given the distance of the boat from the shore

From the provided data, we can easily find the time taken by the sound to reach the shore using the second equation of motion

s = ut + 1/2 at²

since the acceleration of sound is 0:

s = ut + 1/2 (0)t²

s = ut    <em>(here, u is the speed of sound , s is the distance travelled and t is the time taken)</em>

Replacing the variables in the equation with the values we know

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t = 1200 / 343

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Therefore, the sound of the gun will be heard at the shore, 3.5 seconds after being fired

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