The capacitance of the capacitor is ![1.8\cdot 10^{-9}F](https://tex.z-dn.net/?f=1.8%5Ccdot%2010%5E%7B-9%7DF)
Explanation:
The capacitance of a parallel-plate capacitor is given by the equation
![C=\frac{k\epsilon_0 A}{d}](https://tex.z-dn.net/?f=C%3D%5Cfrac%7Bk%5Cepsilon_0%20A%7D%7Bd%7D)
where
k is the dielectric constant of the medium
is the vacuum permittivity
A is the area of the plates
d is the separation between the plates
For the capacitor in this problem, we have:
k = 2.1 is the dielectric constant
is the separation between the plates
(I assumed that 5.4 m is a typo, since it is not a realistic size for the side of the plate)
Therefore, the capacitance of the capacitor is
![C=\frac{(2.1)(8.85\cdot 10^{-12})(0.0034)}{3.5\cdot 10^{-5}}=1.8\cdot 10^{-9}F](https://tex.z-dn.net/?f=C%3D%5Cfrac%7B%282.1%29%288.85%5Ccdot%2010%5E%7B-12%7D%29%280.0034%29%7D%7B3.5%5Ccdot%2010%5E%7B-5%7D%7D%3D1.8%5Ccdot%2010%5E%7B-9%7DF)
Learn more about capacitors:
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