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RoseWind [281]
3 years ago
10

A proton moves at constant velocity in the direction, through a region in which there is an electric field and a magnetic field.

The electric field is in the direction, and has magnitude 800 V/m. The magnetic field is in the direction, and has magnitude 0.25 T. Collapse question part Part 1 Incorrect answer. Your answer is incorrect. Try again. What is the magnitude of the net force on the proton?
Physics
1 answer:
dimaraw [331]3 years ago
7 0

Answer:

F_{net}=0

Explanation:

It is given that, a proton moves at constant velocity, through a region in which there is an electric field and a magnetic field such that,

The electric field is, E = 800 V/m

Magnetic field, B = 0.25 T

We know that the net force in the region of magnetic and electric field is given by Lorentz forces. But here, the proton moves with constant velocity. So, the net force acting on it is 0.

i.e.

F_{net}=0

Hence, this is the required solution.

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Read 2 more answers
9. A car driver brakes gently. Her car slows down front --
sleet_krkn [62]

Answer:

9) This is a case of deceleration

10)-0.8 ms-2

b) acceleration is the change in velocity with time

11)

a) 100 ms-1

b) 100 seconds

12) 10ms-1

13) more information is needed to answer the question

14) - 0.4 ms^-2

15) 0.8 ms^-2

Explanation:

The deceleration is;

v-u/t

v= final velocity

u= initial velocity

t= time taken

20-60/50 =- 40/50= -0.8 ms-2

11)

Since it starts from rest, u=0 hence

v= u + at

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v= 100 ms-1

b)

v= u + at but u=0

1000 = 10 t

t= 1000/10

t= 100 seconds

12) since the sprinter must have started from rest, u= 0

v= u + at

v= 5 × 2

v= 10ms-1

14)

v- u/t

10 - 20/ 25

10/25

=- 0.4 ms^-2

15)

a=v-u/t

From rest, u=0

8 - 0/10

a= 8/10

a= 0.8 ms^-2

7 0
4 years ago
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Answer:

Complete the following table. Be sure to include units in your answer.

Explanation:

all you have to do is mautiply them

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