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omeli [17]
1 year ago
8

Which hybrid orbitals overlap to form the sigma bonds between the indicated atoms in xanthine?

Chemistry
1 answer:
amid [387]1 year ago
8 0

Answer:

C.) Csp² - Nsp³

Explanation:

Because the carbon has only 3 unique bonds, the conformation of the carbon should be Csp² (s + p + p). While the nitrogen also has only 3 bonds, making up 3 orbitals, it also has a lone pair of electrons. These electrons also take up one orbital. Therefore, the conformation of nitrogen is Nsp³ (s + p + p + p).

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A student measures the mass of a 10m^3 block of gold to be 500 kg what is the density of the gold
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d = 50 kg/m³

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density = \frac{mass}{volume}

mass = 500 kg

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\frac{500}{10} = 50

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Explain why the structure of Copper [ 1s², 2s², 2p⁶, 3s², 3p⁶, 3d¹⁰,4s¹] is more stable than [ 1s², 2s², 2p⁶, 3s, 3p²⁶, 3d⁹,4s²
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Read 2 more answers
In which reaction does the oxidation number of hydrogen change? In which reaction does the oxidation number of hydrogen change?
dedylja [7]

<u>Answer:</u> The correct answer is 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

<u>Explanation:</u>

Oxidation number is defined as the number which is given to an atom when it looses or gains electron. When an atom looses electron, it attains a positive oxidation state. When an atom gains electron, it attains a negative oxidation state.

Oxidation state of the atoms in their elemental state is considered as 0. Hydrogen is present as gaseous state.

For the given chemical reactions:

  • <u>Reaction 1:</u>  2HClO_4(aq.)+CaCO_3(s)\rightarrow Ca(ClO_4)_2(aq.)+H_2O(l)+CO_2 (g)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 2:</u>  CaO(s)+H_2O(l)\rightarrow Ca(OH)_2(s)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 3:</u>  HCl(aq.)+NaOH(aq.)\rightarrow NaCl(aq.)+H_2O(l)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 4:</u>  2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: 0

Thus, the oxidation state of hydrogen is changing.

  • <u>Reaction 5:</u>  SO_2(g)+H_2O(l)\rightarrow H_2SO_3(aq.)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

Hence, the correct answer is 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

6 0
3 years ago
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