What atoms in water are attracted to Chlorine?

A 5.00 L flask contains 7.94 g of a gas at STP. What is the molar mass of the gas?

Rashid [163]

Answer: 35.6 g/mol

Explanation: I guessed and got it correct

5 0

2 years ago

A sealed container holding 0.0255 L of an ideal gas at 0.979 atm and 67 ∘ C is placed into a refrigerator and cooled to 41 ∘ C w

Aliun [14]

Answer:

$0.904 atm$

Explanation:

Using Gay Lusaac's law where there is no change in Volume. The pressure changes directly proportional to absolute T°

P₁/T₁ = P₂/T₂

P₁T₂/T₁

P₂ = $\frac{0.979 atm * 314k }{340k}$

P₂ = $0.904 atm$

5 0

3 years ago

¿cual es la expresion matematica para dos magnitudes que se relacionan de una forma directamente proporcional?

DENIUS [597]

Answer:

4

Explanation:

I guess it says more about the problem

3 0

2 years ago

calculate the wavelength of light associated with the transition from n=1 to n=3 in the hydrogen atom?

inessss [21]

Answer:

$\Delta E=E_{final}-E_{initial}$

$\Delta E=-1312[\frac{1}{(n_f^2)}-\frac {1}{(n_i^2 )}]KJ mol^{-1}$

$\Delta E=-1312[\frac{1}{3^2)}-\frac {1}{(1^2 )}]KJ mol^{-1}$

$\Delta E=-1312[\frac{1}{(9)}-\frac {1}{(1 )}]KJ mol^{-1}$

$\Delta E=-1312[0.111-1]KJ mol^{-1}$

$\Delta E=1166 KJ mol^{-1}$

$\frac{=1166,000 \mathrm{J}}{6.022 \times 10^{23} \text { photons }}$

$=193623 \times 10^{-23} \frac {J}{photon}$

$\Delta E=1.93623 \times 10^{-18} \frac {J}{photon}$

$\Delta E=\frac {h\times c}{\lambda} \\\\=\frac {(6.626\times 10^{-34} J s \times 3 \times 10^8 ms^{-1})}{\lambda}$

h is planck's constant

c is the speed of light

λ is the wavelength of light

$\lambda =\frac {h\times c}{\Delta E}\\\\=\frac {(6.626\times10^{-34} J s\times3 \times 10^8 ms^{-1})}{(1.93623\times10^{-18} J/photon)}$

Wavelength

$\lambda =10.3 \times 10^{-8} m \times \frac {(10^9 nm)}{1m} =103 nm (Answer)$

Thus, the wavelength of light associated with the transition from n=1 to n=3 in the hydrogen atom is 103 nm.

7 0

3 years ago

Highlight the examples of radiation in the passage

BartSMP [9]

Answer:

Heating of the liquid water in a microwave.

Explanation:

Radiation is a form of heat transfer process that does not require a material medium rather it travels through space or vacuum in the form of electromagnetic waves or radiation. Heat transfer by radiation occurs in the form of microwaves, infrared radiation, visible light, or another form of electromagnetic radiation is emitted or absorbed. Some common examples of heat transfer by radiation is the warming of the Earth by the Sun, the warmth one experiences while sitting by the campfire, or the heating up of foods in a microwave.

Black bodies or surfaces are good absorbers as well as emitters of radiation. On the other shiny or white surfaces are poor radiators of heat.

From the above discussion on radiation, it can be seen that when the chemist takes the liquid and heats it in a microwave, the heat absorbed by the liquid to change to gaseous state is transferred through radiation.

5 0

2 years ago