The answer would be intoduction hope this really helped
Answer:
Earth and Venus has similar size, mass and density. Both have a very similar composition, But atmosphere of Venus is composed only of carbon dioxide is not similar to Earth.
Explanation:
my mind
Answer:
Magnitude of induced emf is 0.00635 V
Explanation:
Radius of circular loop r = 45 mm = 0.045 m
Area of circular loop ![A=\pi r^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2)
![A=3.14\times 0.045^2=0.00635m^2](https://tex.z-dn.net/?f=A%3D3.14%5Ctimes%200.045%5E2%3D0.00635m%5E2)
Magnetic field is increases from 250 mT to 350 mT
Therefore change in magnetic field ![dB=250-350=100mT](https://tex.z-dn.net/?f=dB%3D250-350%3D100mT)
Emf induced is given by
![e=-N\frac{d\Phi }{dt}=-NA\frac{dB}{dt}](https://tex.z-dn.net/?f=e%3D-N%5Cfrac%7Bd%5CPhi%20%7D%7Bdt%7D%3D-NA%5Cfrac%7BdB%7D%7Bdt%7D)
![e=-0.00635\times \frac{100\times 10^{-3}}{0.10}=-0.00635V](https://tex.z-dn.net/?f=e%3D-0.00635%5Ctimes%20%5Cfrac%7B100%5Ctimes%2010%5E%7B-3%7D%7D%7B0.10%7D%3D-0.00635V)
Magnitude of induced emf is equal to 0.00635 V
Answer:
The lenses with different focal length are four.
Explanation:
Given that,
Radius of curvature R₁= 4
Radius of curvature R₂ = 8
We know ,
Refractive index of glass = 1.6
When, R₁= 4, R₂ = 8
We need to calculate the focal length of the lens
Using formula of focal length
![\dfrac{1}{f}=(n-1)(\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}})](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D%28n-1%29%28%5Cdfrac%7B1%7D%7BR_%7B1%7D%7D%2B%5Cdfrac%7B1%7D%7BR_%7B2%7D%7D%29)
Put the value into the formula
![\dfrac{1}{f}=(1.6-1)(\dfrac{1}{4}+\dfrac{1}{8})](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D%281.6-1%29%28%5Cdfrac%7B1%7D%7B4%7D%2B%5Cdfrac%7B1%7D%7B8%7D%29)
![\dfrac{1}{f}=\dfrac{9}{40}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D%5Cdfrac%7B9%7D%7B40%7D)
![f=4.44\ cm](https://tex.z-dn.net/?f=f%3D4.44%5C%20cm)
When , R₁= -4, R₂ = 8
Put the value into the formula
![\dfrac{1}{f}=(1.6-1)(\dfrac{1}{-4}+\dfrac{1}{8})](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D%281.6-1%29%28%5Cdfrac%7B1%7D%7B-4%7D%2B%5Cdfrac%7B1%7D%7B8%7D%29)
![\dfrac{1}{f}=-\dfrac{3}{40}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D-%5Cdfrac%7B3%7D%7B40%7D)
![f=-13.33\ cm](https://tex.z-dn.net/?f=f%3D-13.33%5C%20cm)
When , R₁= 4, R₂ = -8
Put the value into the formula
![\dfrac{1}{f}=(1.6-1)(\dfrac{1}{4}-\dfrac{1}{8})](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D%281.6-1%29%28%5Cdfrac%7B1%7D%7B4%7D-%5Cdfrac%7B1%7D%7B8%7D%29)
![\dfrac{1}{f}=\dfrac{3}{40}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D%5Cdfrac%7B3%7D%7B40%7D)
![f=13.33\ cm](https://tex.z-dn.net/?f=f%3D13.33%5C%20cm)
When , R₁= -4, R₂ = -8
Put the value into the formula
![\dfrac{1}{f}=(1.6-1)(\dfrac{1}{-4}-\dfrac{1}{8})](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D%281.6-1%29%28%5Cdfrac%7B1%7D%7B-4%7D-%5Cdfrac%7B1%7D%7B8%7D%29)
![\dfrac{1}{f}=-\dfrac{9}{40}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bf%7D%3D-%5Cdfrac%7B9%7D%7B40%7D)
![f=-4.44\ cm](https://tex.z-dn.net/?f=f%3D-4.44%5C%20cm)
Hence, The lenses with different focal length are four.
Answer:
W = 0.49 N
τ = 0.4851 Nm
Force
Explanation:
The weight force can be found as:
W = mg
W = (0.05 kg)(9.8 m/s²)
<u>W = 0.49 N</u>
The torque about the pivot can be found as:
τ = W*d
where,
τ = torque
d = distance between weight and pivot = 99 cm = 0.99 m
Therefore,
τ = (0.49 N)(0.99 m)
<u>τ = 0.4851 Nm</u>
The pivot exerts a <u>FORCE </u>on the meter stick because the pivot applies force normally over the stick and has a zero distance from stick.