1 year ago

A 5OKG mass is taken to the moon and the mass determined there, comment on the likely result of the measurement

Physics

1 answer:

vodomira [7]1 year ago

7 0

Answer:

Mass will be the same

Explanation:

Mass does not change with gravity .... WEIGHT will be different, but not mass.

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A synthesis reaction occurs when a substance breaks down into two or more simple

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True . this is called a complex substance

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3 years ago

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What is the desired tone of an instrument called?

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Timbre also known as color or tone quantity which is used for music notes sound and tone are mostly know for guitars or pianos .

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A certain white dwarf star was once an average star like our Sun. But now it is in the last stage of its evolution and is the si

solmaris [256]

Answer:

4.384 * 10^13

Explanation:

Given the expression :

[(6.67 * 10^-11) * (1.99 * 10^30)] ÷ [(1.74*10^3)*(1.74*10^3)]

Applying the laws of indices

[(6.67 * 1.99) *10^(-11 + 30)] ÷ [(1.74 * 1.74) * 10^3+3]

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(13.2733 / 3.0276) * 10^(19 - 6)

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2 years ago

Calculate earth's mass given the acceleration due to gravity at the north pole is 9.830 m/s2 and the mean radius of the earth at

valentinak56 [21]

Answer: $M = 5.98\times 10^{24} kg$

Explanation:

We know that force acting on an object due to Earth's gravity on the surface is given by:

$mg = G\frac{Mm}{r^2}\\ \Rightarrow g = \frac{GM}{r^2}$

where g is the acceleration due to gravity, r would be radius of Earth, M is the mass of Earth and G is the gravitational constant.

It is given that at pole, g = 9.830 m/s² and r = 6371 km = 6371 × 10³ m

$\Rightarrow M = \frac{g\times r^2}{G}$

$M = \frac{9.830 m/s^2 \times (6371 \times 10^3 m )^2}{6.67 \times 10^{-11} m^3 kg^{-1} s^{-2}}$

$\Rightarrow M = 5.98\times 10^{24} kg$

Hence, Earth's mass is $5.98\times 10^{24} kg$

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3 years ago

Please help answer the question in the screenshot. it's multiple choice..

Talja [164]

Answer:

Since F = G * m1 * m2 / r^2

F = 6.67 * 19E-11 * 2.79 * 9.47 * 10E23 / (1.2 * 10^7)^2

F = 126 * 10E-2 N = 1.22 N

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3 years ago