Answer: v = 3.57×10^6 m/s; R = 4.42×10^-3m; T = 7.78×10^-9 s
Explanation:
Magnetic force(B) = 4.60×10^-3 T
Electric force(E) = 1.64×10^4 V/m
Both forces having equal magnitude ;
Magnetic force = electric force
qvB = qE
vB = E
v = (1.64×10^4) ÷ (4.60×10^-3)
v = 3.57×10^6 m/s
2.) Assume no electric field
qvB = ma
Where a = v^2 ÷ r
R = radius
a = acceleration
v = velocity
qvB = m(v^2 ÷ R)
R = (m×v) ÷ (|q|×B)
q=1.6×10^-19C
m = 9.11×10^-31kg
R = (9.11×10^-31 * 3.57×10^6) ÷ (1.6×10^-19 * 4.6×10^-3)
R = 32.5227×10^-25 ÷ 7.36×10^-22
R = 4.42×10^-3m
3.) period(T)
T = (2*pi*R) ÷ v
T = (2* 4.42×10^-3 * 3.142) ÷ (3.57×10^6)
T = (27.775×10^-3) ÷(3.57×10^6)
T = 7.78×10^-9 s
<h2>
Answer: True </h2><h2>
</h2>
Each atom emits or absors electromagnetic radiation, but only in some frequencies that are characteristic of its chemical element.
Now, if we supply energy in the form of heat (thermal energy) to a certain element in its gas phase, this will be stimulated and its atoms will emit radiation in certain frequencies of the visible spectrum, which constitute its <u>emission spectrum</u>.
If the same element, also in gaseous state, receives electromagnetic radiation, it absorbs in certain frequencies of the visible spectrum, <u>precisely the same ones in which it emits when it is stimulated by heat</u>. This will be its <u>absorption spectrum.</u>
<h2>
This means that every element absorbs radiation in the same wavelengths in which it emits it. </h2>
Answer:
Supongo que quieres encontrar las relaciones que te permiten cambiar las escalas de temperatura.
Las 3 escalas de temperatura son:
°C = grado Celcius.
°F = grado Farenheit.
K = grado Kelvin.
Empezamos con °C, pues es la mas conocida.
La diferencia entre consecutivos grados es la misma en la escala Kelvin que en la escala Celcius, pero la escala Kelvin esta definida de tal forma que el cero Kelvin representa la ausencia absoluta de temperatura, mientras que en Celcius podemos tener temperaturas menores a 0 grados.
La transformación entre Celcius y Kelvin es:
x °C = (x + 273.15) K
Es decir, agarramos nuestra temperatura en °C, y le sumamos 273.15 grados.
La transformación entre Celcius y Farenheit es:
x °C = ((x*9/5) + 32) °F
Y la faltante, va a ser de Kelvin a Farenheit, que es:
x K = ( ( (x - 273.15)*9/5) + 32) °F
Answer:
Explanation:
According to the Principle of Energy Conservation and the Work-Energy Theorem, the bullet has the following expression:
![F\cdot \Delta s = \frac{1}{2}\cdot m \cdot [v_{A}^{2}-v_{B}^{2}]](https://tex.z-dn.net/?f=F%5Ccdot%20%5CDelta%20s%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20m%20%5Ccdot%20%5Bv_%7BA%7D%5E%7B2%7D-v_%7BB%7D%5E%7B2%7D%5D)
The average force exerted on the bullet to stop it is:
![F = \frac{m\cdot [v_{A}^{2}-v_{B}^{2}]}{2\cdot \Delta s}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7Bm%5Ccdot%20%5Bv_%7BA%7D%5E%7B2%7D-v_%7BB%7D%5E%7B2%7D%5D%7D%7B2%5Ccdot%20%5CDelta%20s%7D)
![F = \frac{(7.8\times 10^{-3}\,kg)\cdot [(540\,\frac{m}{s} )^{2}-(0\,\frac{m}{s} )^{2}]}{2\cdot (0.051\,m)}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7B%287.8%5Ctimes%2010%5E%7B-3%7D%5C%2Ckg%29%5Ccdot%20%5B%28540%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%5E%7B2%7D-%280%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%5E%7B2%7D%5D%7D%7B2%5Ccdot%20%280.051%5C%2Cm%29%7D)
