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OLga [1]
3 years ago
9

Do metal atoms tend to gain or lose electrons?

Physics
2 answers:
german3 years ago
6 0
<span>The elements of the periodic table are classified into three categories: inert gases, nonmetals and metals. Generally, inert gases do not readily gain nor lose electrons, while nonmetals are more likely to acquire electrons. Metals contain low ionization energies, which refer to the amount of energy required to free or remove an electron. These elements also have low electron affinities, or the attractive forces between an incoming electron and the nucleus of an atom. The lower the ionization energies and electron affinities of an atom are, the greater the tendency to lose electrons.</span>
Solnce55 [7]3 years ago
3 0
<span>Metal atoms have the tendency to lose electrons. The type of chemical bonding formed by atoms of metallic elements is called metallic bonding.</span><span>In terms of gaining or losing electrons, the elements of the periodic table are classified into three categories: inert gases, nonmetals and metals. Generally, inert gases do not readily gain nor lose electrons, while nonmetals are more likely to acquire electrons. Metals contain low ionization energies, which refer to the amount of energy required to free or remove an electron. These elements also have low electron affinities, or the attractive forces between an incoming electron and the nucleus of an atom. The lower the ionization energies and electron affinities of an atom are, the greater the tendency to lose electrons.</span> 
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Unpolarized light with intensity I0I0I_0 is incident on an ideal polarizing filter. The emerging light strikes a second ideal po
zvonat [6]

Answer:

0.293I_0

Explanation:

When the unpolarized light passes through the first polarizer, only the component of the light parallel to the axis of the polarizer passes through.

Therefore, after the first polarizer, the intensity of light passing through it is halved, so the intensity after the first polarizer is:

I_1=\frac{I_0}{2}

Then, the light passes through the second polarizer. In this case, the intensity of the light passing through the 2nd polarizer is given by Malus' law:

I_2=I_1 cos^2 \theta

where

\theta is the angle between the axes of the two polarizer

Here we have

\theta=40^{\circ}

So the intensity after the 2nd polarizer is

I_2=I_1 (cos 40^{\circ})^2=0.587I_1

And substituting the expression for I1, we find:

I_2=0.587 (\frac{I_0}{2})=0.293I_0

5 0
2 years ago
Anaerobic transmission is when you touch a contaminated surface true or false
Keith_Richards [23]
True because my mom said to me this morning that i have to take my breakfast
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2 years ago
Which of the following universal forces is the most effective over long distances?
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Electrical forces travel far through the universe
5 0
3 years ago
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Calculate the resistance of an electric bulb which allows a 10 A current when connected to a 220 V power source
kodGreya [7K]

Resistance can be calculated by Ohm's law

As per ohm's law we will have

V = i * R

here we will have

voltage = 220 volts

current = 10 A

So by the above formula we will have

220 = 10* R

R = 22 ohm

So resistance of the bulb is 22 ohm.

4 0
3 years ago
A ship sets out to sail to a point 154 km due north. An unexpected storm blows the ship to a point 72 km due east of its startin
Norma-Jean [14]

Answer:

<h2>170km</h2>

Explanation:

If a ship sets out to sail to a point 154 km due north and an unexpected storm blows the ship to a point 72 km due east of its starting point, then the ships distance from the original destination can be gotten by finding the displacement of the ship and this can be gotten by using pythagoras theorem.

Let D be the unknown displacement

According to the theorem;

D² = 154² + 72²

D² = 23716 + 5184

D² = 28900

D = √28900

D = 170km

<em>This means that the ship must now sail a distance of 170km for it to reach its original destination.</em>

8 0
3 years ago
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