Answer:
Explanation:
a) Force of friction = μ R where μ is coefficient of kinetic friction and R is reaction force
R = mg where m is mass of the block
Force of friction F = μ x mg
= .173 x 12.2 x 9.8
= 20.68 N
b ) Only force of friction is acting on the body so
deceleration = force / mass = 20.68 / 12.2 = 1.7 m /s²
acceleration = - 1.7 m /s²
c )
v² = u² - 2 a s
v = 0 , u = 3.9 m /s
a = 1.7 m /s
0 = 3.9² - 2 x 1.7 x s
s = 4.47 m
Answer:
+ 0.07 C
Explanation:
From the question given above, the following data were obtained:
Potential difference (V) = 12 V
Energy (E) = 0.418 J
Charge (Q) =?
The energy (E) , potential difference (V) and charge (Q) are related by the following equation:
E = ½QV
With the above formula, we can obtain the charge as follow:
Potential difference (V) = 12 V
Energy (E) = 0.418 J
Charge (Q) =?
E = ½QV
0.418 = ½ × Q × 12
0.418 = Q × 6
Divide both side by 6
Q = 0.418 / 6
Q = + 0.07 C
Explanation:
Given that,
Mass, m = 0.08 kg
Radius of the path, r = 2.7 cm = 0.027 m
The linear acceleration of a yo-yo, a = 5.7 m/s²
We need to find the tension magnitude in the string and the angular acceleration magnitude of the yo‑yo.
(a) Tension :
The net force acting on the string is :
ma=mg-T
T=m(g-a)
Putting all the values,
T = 0.08(9.8-5.7)
= 0.328 N
(b) Angular acceleration,
The relation between the angular and linear acceleration is given by :

(c) Moment of inertia :
The net torque acting on it is,
, I is the moment of inertia
Also, 
So,

Hence, this is the required solution.
It’s 12 km
Because you multiply 8x1.5 and you get the answer.
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