Jsudjdndkdjddjdjxixidjdjxjx
Answer:
E_total = 1.30 10¹⁰ C / m²
Explanation:
The intensity of the electric field is
E = k q / r²
on a positive charge proof
The total electric field at the midpoint is
as q₁= 6 10⁻⁶ C the field is outgoing to the right
for charge q₂ = -3 10⁻⁶ C, the field is directed to the right, therefore
E_total = E₁ + E₂
E_total = k q₁ / r₁² + k q₂ / r₂²
r₁ = r₂ = r = 4 10⁻² m
E_total = k/r² (q₁ + q₂)
we calculate
E_total = 9 10⁹ / (4 10⁻²)² (6.0 10⁻⁶ +3.0 10⁻⁶)
E_total = 1.30 10¹⁰ C / m²
increase because the heavier it is the more gravitational pull it has.
Answer:
3.03 m/s²
Explanation:
m₂ > m₁, so m₁ will move up, m₂ will move down, and m₃ will move to the right.
Sum of the forces on m₁:
∑F = ma
T₁ − m₁g = m₁a
T₁ = m₁g + m₁a
Sum of the forces on m₂:
∑F = ma
T₂ − m₂g = m₂(-a)
T₂ = m₂g − m₂a
Sum of the forces on m₃ in the y direction:
∑F = ma
N − m₃g = 0
N = m₃g
Sum of the forces on m₃ in the x direction:
∑F = ma
T₂ − T₁ − F = m₃a
T₂ − T₁ − Nμ = m₃a
Substituting and solving for acceleration:
(m₂g − m₂a) − (m₁g + m₁a) − (m₃g)μ = m₃a
m₂g − m₂a − m₁g − m₁a − m₃gμ = m₃a
g (m₂ − m₁ − m₃μ) = (m₁ + m₂ + m₃) a
a = g (m₂ − m₁ − m₃μ) / (m₁ + m₂ + m₃)
Given m₁ = 4 kg, m₂ = 12 kg, m₃ = 6 kg, and μ = 0.2:
a = 9.81 (12 − 4 − 6×0.2) / (4 + 12 + 6)
a = 3.03 m/s²
Answer:
Over Here
Explanation:
Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.