Answer:
(a). The electric potential at 1.650 cm is
.
(b). The electric potential at 2.81 cm is
.
Explanation:
Given that,
Radius of sphere R=2.81 cm
Charge = +2.35 fC
Potential at center of sphere

(a). We need to calculate the potential at a distance r = 1.60 cm
Using formula of potential difference






The electric potential at 1.650 cm is
.
(b). We need to calculate the potential at a distance r = R
Using formula of potential difference



The electric potential at 2.81 cm is
.
Hence, This is the required solution.
Answer:
I wanna say 4 I'm not sure though
Answer:
A)F
B)F
C)T
Explanation:
A)
This is not always true that the product of the two vector's always non-negative .It may be positive or negative.
That is why this statement is false.
B)
The unit vectors in three perpendicular direction is i ,j and k.
We know that for unit vectors
i.i=j.j=k.k= 1
i .j= j.k=k.i=0
Therefore only parallel component of the force will contribute in the integral part instead of perpendicular component of the force.
That is why this statement is false.
C)
This statement is True.
A)F
B)F
C)T
Answer:
The value 
Explanation:
From the question we are told that
The volume blood ejected is 
The velocity of the blood ejected is 
The density of blood is 
The heart beat is 
The average force exerted by the blood on the wall of the aorta is mathematically represented as

=> 
=> 
Answer:
The distance travel before stopping is 1.84 m
Explanation:
Given :
coefficient of kinetic friction 
Zak's speed 
Gravitational acceleration

Work done by frictional force is given by,




m
Therefore, the distance travel before stopping is 1.84 m