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Slav-nsk [51]
3 years ago
15

You exert a 138 N push the leftmost of two identical blocks of mass 244 g connected by a spring of stiffness 605 kg/s2. After pu

shing the block a distance 15 cm, you release it; by this time the rightmost block has moved a distance 5 cm. (a) What is the energy in the oscillations between the blocks
Physics
1 answer:
Reil [10]3 years ago
6 0

Answer:

the energy in the oscillations between the blocks is 3.025 J

Explanation:

Given the data in the question;

Force f = 138 N

stiffness of spring k = 605 kg/s²

mass of block = 202 g = 0.202 kg

pushing the block a distance 15 cm, the rightmost block has moved a distance 5 cm

i.e

x₁ = 15 cm

x₂ = 5cm

the energy in the oscillations between the blocks will be;

E_A = E_B = \frac{1}{2}k( Δx )²

we substitute

= \frac{1}{2} × k( 15 - 5 )² × 10⁻⁴

= \frac{1}{2} × 605 × ( 10 )² × 10⁻⁴

= \frac{1}{2} × 605 × 100 × 10⁻⁴

= 3.025 J

Therefore, the energy in the oscillations between the blocks is 3.025 J

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Explanation:

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3 years ago
Suppose a rectangular piece of aluminum has a length D, and its square cross section has the dimensions W XW, where D (W x W) to
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Answer:

R₂ / R₁ = D / L

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We apply this formal to both configurations

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Large face measurements (D L)

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The fluid pressure 10 ft underwater is _____ the fluid pressure 5 ft underwater. A.less than or greater than, depending on what
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The position x, in meters, of an object is given by the equation:
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Answer:

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m,\ m/s\ and\ m/s^2                  

Explanation:

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x=A+Bt+Ct^2

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Answer:

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Explanation:

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