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Slav-nsk [51]
2 years ago
15

You exert a 138 N push the leftmost of two identical blocks of mass 244 g connected by a spring of stiffness 605 kg/s2. After pu

shing the block a distance 15 cm, you release it; by this time the rightmost block has moved a distance 5 cm. (a) What is the energy in the oscillations between the blocks
Physics
1 answer:
Reil [10]2 years ago
6 0

Answer:

the energy in the oscillations between the blocks is 3.025 J

Explanation:

Given the data in the question;

Force f = 138 N

stiffness of spring k = 605 kg/s²

mass of block = 202 g = 0.202 kg

pushing the block a distance 15 cm, the rightmost block has moved a distance 5 cm

i.e

x₁ = 15 cm

x₂ = 5cm

the energy in the oscillations between the blocks will be;

E_A = E_B = \frac{1}{2}k( Δx )²

we substitute

= \frac{1}{2} × k( 15 - 5 )² × 10⁻⁴

= \frac{1}{2} × 605 × ( 10 )² × 10⁻⁴

= \frac{1}{2} × 605 × 100 × 10⁻⁴

= 3.025 J

Therefore, the energy in the oscillations between the blocks is 3.025 J

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