Answer:
Explanation:
<em>Given equation:</em>
<em>
</em>
<em>To </em><em>find:</em>
Limiting reactant for corresponding number of moles=?
<em>Solution:</em>
We know that the liming reactant is any atom, ion or molecule which is completely consumed during a reaction and other reactant is still left in reactant vessel.
For the given reaction A+3B→C
for every one mole of A three moles of B are required.
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in A) there is one mole of A and 4 mole of B,
if 1 mole of A will react with 3 moles of B, 1 mole of B will be still there in reaction, the reactant was completely consumed is A which is limiting reactant.
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in B) there is 2 mole of A and 3 mole of B,
if 1 mole of A will react with 3 moles of B, 1 mole of A will be still there in reaction, the reactant was completely consumed is B which is limiting reactant.
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in C) there is 0.5 mole of A and 1.6 mole of B
if one mole of A requires three moles of B to complete the reaction then,
0.5 moles of A will require 1.5 moles of B
if 0.5 mole of A will react with 1.6 moles of B, 0.1 mole of B will be still there in reaction, the reactant was completely consumed is A which is limiting reactant.
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in D) there is 24 mole of A and 72 mole of B
if one mole of A requires three moles of B to complete the reaction then,
24 moles of A will require 72 moles of B.
if 24 mole of A will react with 75 moles of B, 3 mole of B will be left over in reaction, the reactant was completely consumed is A which is limiting reactant.
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= 90.25 kJ/mol
= 0 (For the formation of one mole of a pure element the heat of formation is 0, in this caseyou have as a pure compound the chlorine Cl₂)
=?
