Answer:
The mass of the another block is 60 kg.
Explanation:
Given that,
Mass of block M= 100 kg
Height = 1.0 m
Time = 0.90 s
Let the mass of the other block is m.
We need to calculate the acceleration of each block
Using equation of motion
Put the value into the formula
We need to calculate the mass of the other block
Using newton's second law
The net force of the block M
....(I)
The net force of the block m
Put the value of T from equation (I)
Put the value into the formula
Hence, The mass of the another block is 60 kg.
Answer:
2.47 s
Explanation:
Convert the final velocity to m/s.
We have the acceleration of the gazelle, 4.5 m/s².
We can assume the gazelle starts at an initial velocity of 0 m/s in order to determine how much time it requires to reach a final velocity of 11.1111 m/s.
We want to find the time t.
Find the constant acceleration equation that contains all four of these variables.
Substitute the known values into the equation.
- 11.1111 = 0 + (4.5)t
- 11.1111 = 4.5t
- t = 2.469133333
The Thompson's gazelle requires a time of 2.47 s to reach a speed of 40 km/h (11.1111 m/s).
D) both air temperature and medium
Answer:
Given mass = 2kg, height = 1.2m,g = 9.8.
We know that Work done W = FD
= > W = (mg)(D)
= > W = (2 * 9.8)(1.2)
= > W = 23.52 Joules.
<span>Angular distance moved = 220 rad = {35(2π) ≈ 220 rad}
Max angular speed = 18 rad/s
Final angular speed = 0 rad/s
Avg angular speed = 9 rad/s {assuming a CONSTANT de-celeration of wheel}
Time to stop = 220/9 = 24.4 s ANS</span>