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vlabodo [156]
2 years ago
6

Please solve the Problem.

Physics
1 answer:
andrey2020 [161]2 years ago
8 0

The frequency heard by the moth is the frequency emitted by the bat by virtue of its speed; 38.0kHz. B) If the speed of the bat is increased, the frequency heard by the moth is higher.

<h3>What is the frequency heard by the moth?</h3>

It follows from the task content that the frequency of the emitted by the bat is heard by the moth and hence, the frequency heard by the moth is; 38kHz.

B) Since, the speed and frequency of sound waves are directly proportional, speed = wavelength × frequency; it therefore follows that when the speed of the bat is increased, the frequency heard by the moth is higher.

Read more on speed and frequency;

brainly.com/question/10728818

#SPJ1

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Two charged particles are a distance of 1.72 m from each other. One of the particles has a charge of 7.03 nC, and the other has
MaRussiya [10]

A. The magnitude (in N) of the electric force that one particle exerts on the other is 8.60×10⁻⁸ N

B. The force is repulsive

<h3>A. How to determine the magnitude of the electric force</h3>

From the question given above, the following data were obtained:

  • Charge 1 (q₁) = 7.03 nC = 7.03×10¯⁹ C
  • Charge 2 (q₂) = 4.02 nC = 4.02×10¯⁹ C
  • Electric constant (K) = 9×10⁹ Nm²/C²
  • Distance apart (r) = 1.72 m
  • Force (F) =?

The magnitude of the electric force can be obtained by using the Coulomb's law equation as shown below:

F = Kq₁q₂ / r²

F = (9×10⁹ × 7.03×10¯⁹ × 4.02×10¯⁹) / (1.72)²

F = 8.60×10⁻⁸ N

<h3>B. How to determine whether the force is attractive or repulsive</h3>

From the question given, we were told that:

  • Charge 1 (q₁) = 7.03 nC
  • Charge 2 (q₂) = 4.02 nC

Since both charge are positive, then the force attraction between them is repulsive as like charges repels and unlike charges attracts

Learn more about Coulomb's law:

brainly.com/question/506926

#SPJ1

4 0
2 years ago
Read 2 more answers
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