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Bezzdna [24]
3 years ago
6

Heliox is a helium‑oxygen mixture that may be used in scuba tanks for divers working at great depths. It is also used medically

as a breathing treatment. A 7.25 L tank holds helium gas at a pressure of 1906 psi. A second 7.25 L tank holds oxygen at a pressure of 506.7 psi. The two gases are mixed in a 7.25 L tank. If the temperature remains the same throughout the process, what is the pressure of the gas mixture in the tank? Assume ideal gas behavior.
Physics
1 answer:
maksim [4K]3 years ago
7 0

Answer:

2412 psi is the pressure of the gas mixture in the tank.

Explanation:

Pressure of the helium gas = 1,906 psi

Volume of the helium gas = 7.25 L

Pressure of the oxygen gas = 506 psi

Volume of the oxygen gas = 7.25 L

After mixing both gases in a container with volume 7.25 L at with constant temperature.

Since, the temperature and volume remained constant, pressure becomes directly dependent on moles of gases.So, when we mix gases together the moles of gases will also add and along with that pressure of individual gas will also get added to give total pressure of the mixture in a tank.

Total pressure = pressure(Heluim)+pressure(oxygen)

P_{total}=1,906 psi+506 psi=2,412 psi

2412 psi is the pressure of the gas mixture in the tank.

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Mark all of the antimatter particlesa) Proton b) Electron c)Anti-top d) Gluon e) Tau Neutrino
Bond [772]

Answer:

c) Anti-top

Explanation:

Protons are particles which belong to the hadron group of particles. The antimatter equivalent particle is antiproton

Electrons are particles that belong to the fermion group of particles. The antimatter equivalent is antielectron

Antitop quarks are particles that belong to the group family of particles. They are the antimatter equivalent of top quarks.

Gluons are particles that belong to the group of particles called bosons.

Tau neutrinos are particles that belong to the fermion group of particles. The antimatter equivalent is Tau antineutrino.

3 0
2 years ago
A block of mass m slides with a speed vo on a frictionless surface and collides with another mass M which is initially at rest.
Rudik [331]

To solve this problem we will apply the concepts related to the conservation of momentum. Momentum can be defined as the product between mass and velocity. We will depart to facilitate the understanding of the demonstration, considering the initial and final momentum separately, but for conservation, they will be later matched. Thus we will obtain the value of the mass. Our values will be defined as

m_1 = m

m_2 = M

v_{1i} =v_0

v_{2i} = 0

Initial momentum will be

P_i = m_iv_{1i}+m_2v_{2i}

P_i = mv_0

After collision

v_{1f} = v_{2f} = \frac{v_0}{3}

Final momentum

P_f = (m_1+m_2)(\frac{v_0}{3})

P_f = (m+M)(\frac{v_0}{3})

From conservation of momentum

P_f = P_i

Replacing,

(m+M)(\frac{v_0}{3})=mv_0

(m+M)\frac{1}{3} = m

m+M=3m

M=3m-m

M=2m

3 0
3 years ago
3. Ultraviolet can kill these. <br><br>8words and 2nd letter starts with an A​
Karo-lina-s [1.5K]

Answer:

Bacteria

Explanation:

UV kills bacteria and its 8 letters

7 0
3 years ago
Jamal is skating on a sidewalk. His initial velocity is 0.0 m/s; 35 seconds later his velocity is 5.0 m/s. What is his accelerat
maxonik [38]

Answer:

answer is 0.1428

Explanation:

Data:- vf=5.0 , vi=0.0 , t=35 , a=? so appling first eq of motion vf=vi+at we have to find a=vf-vi/t , a=5.0-0.0/35 , a=5/35 ,a=0.1428m/sec²

5 0
3 years ago
Read 2 more answers
Two resistors R1 = 3 Ω and R2 = 6 Ω are connected in parallel. What is the net resistance in the circuit?​
gtnhenbr [62]

Answer:

"2Ω" is the net resistance in the circuit.

Explanation:

The given resistors are:

R1 = 3Ω

R2 = 6Ω

The net resistance will be:

⇒  \frac{1}{R_{net}} =\frac{1}{R_1} +\frac{1}{R_2}

On substituting the values, we get

⇒  \frac{1}{R_{net}} =\frac{1}{3} +\frac{1}{6}

On taking L.C.M, we get

⇒  \frac{1}{R_{net}} =\frac{2+1}{6}

⇒  \frac{1}{R_{net}} =\frac{3}{6}

⇒  \frac{1}{R_{net}} =\frac{1}{2}

On applying cross-multiplication, we get

⇒ R_{net}=2 \Omega

3 0
2 years ago
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