Comment on the statement "Sharper the curve, more is the bending."
1 answer:
You might be interested in
A car with a velocity of 22 m/s is accelerated at a rate of 1.6 for 6.8s has the final velocity t be 32.88 m/s.
The acceleration means the amount of velocity changing per unit time.
The given data:
initial velocity, u = 22 m/s
time, t = 6.8 s
acceleration, a = 1.6
We will be using the equation of motion:
v = u + at
The final velocity become 32.88 m/s.
To learn more about Attention here:
https://brainly.in/question/10557838
#SPJ4
Answer:
a) 9.00 m b) 6.00 m/s c) 12.00 m/s
Explanation:
a) If the acceleration is constant, and we know that the displacement during the first second was 3.00 m, as the boulder (assumed that we can treat it as a point mass) started from rest, we can say the following:
Δx = = 3.00 m
As t = 1 s, replacing in the expression above, and solving for a, we have:
= 6.00 m/s²
In order to know how far it travels during the second second, we need to know the value of the speed after the first second, as it is the initial velocity when the second second begins:
vf = v₀ + a*t ⇒ vf = 0 + 6 m/s²*1s = 6.00 m/s
The total displacement, during the second second, will be as follows:
Δx = v₀*t + = 6.00m/s*1s +
⇒ Δx = 9.00 m
b) At the end of the first second, the final speed can be obtained as follows:
vf = v₀ + a*t ⇒ vf = 0 + 6 m/s²*1s = 6.00 m/s
c) At the end of the second second, the final speed can be obtained as follows:
vf = v₀ + a*t ⇒ vf = 0 + 6 m/s²*2s = 12.00 m/s