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viva [34]
3 years ago
14

A backpack has a mass of 8 kg. It is lifted and given 54.9 J of gravitational potential energy. How high is it lifted? Accelerat

ion due to gravity is g = 9.8 m/s2.
Physics
2 answers:
sweet [91]3 years ago
8 0
Potencial Energy=hma
Where
Potencial Energy =E= 54.9J
h=?
m=8kg
a=9.8m/s^2
You need to know that 1 J=1(kgm^2)/s^2

Isolate h=E/(ma)
h=(54.9)/(8*9.8)
soldier1979 [14.2K]3 years ago
4 0

Answer: The potential energy for a lifted object is U = m*a*h

where m is the mass, h is the height and a is the acceleration.

in our problem the mass is m = 8kg, the height is the thing we want to find, a is the gravitational acceleration, 9.8 m/s^2 and U = 54.9j

then our problem is:

54.9j = h*9.8*8 kg*m/s^2

then h = 54.9/(9.8*8) = 0.7m

Then the backpack is lifted 0.7 meters.

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(b) Current means charge over time, So, in this case is charge over period:

I=\frac{q}{t}\\I=\frac{e}{T}\\I=\frac{1.6*10^{-19}C}{1.5*10^{-6}s}\\\\I=1.1*10^{-3}A

(c) Magnetic moment is given by:

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\mu=I\pi r^2\\\mu=(1.1*10^{-3}A)\pi(5.3*10^{-11}m)^2\\\mu=9.71*10^{-24}A\cdot m^2

4 0
3 years ago
If a single constant force acts on an object that moves on a straight line, the object's velocity is a linear function of time.
olya-2409 [2.1K]

Answer:

F=mkv

Explanation:

Given that

v = v_i - kx

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a=\dfrac{dv}{dt}

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A student has a small metal sphere that hangs from an insulating string. The student, in seeking to determine the charge on the
Leokris [45]

Answer:

the answer the correct one is c

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Let's analyze the situation presented

* A rod with positive approaches and the sphere is attracted, so the charge on the sphere is negative

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For this to happen, the sphere must be unloaded and the charge that creates the phenomenon are induced charges because the mobile charges of the same sign as the sphere are repelled.

when checking the answer the correct one is c

8 0
3 years ago
A balloon is charged until it has a voltage of v=9800V. A student reaches out and is shocked by a spark. The electric force does
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a)]An expression for the magnitude of charge transferred Q is Q = W/V.

b) The magnitude of the charge, in coulombs is  1.02 x 10⁻⁹ Coulomb.

c) Number of electrons in this are 63.75 x 10⁸ electrons.

<h3>What are electrons?</h3>

The electrons are the spinning objects around the nucleus of the atom of the element in an orbit.

A balloon is charged until it has a voltage of v=9800V. A student reaches out and is shocked by a spark. The electric force does W= 1x10⁻⁶ J of work transferring the charge.

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|Q| =  1x10⁻⁶/9800

|Q| =  1.02 x 10⁻⁹ Coulomb

c) No of electrons  = total charge /charge on electron

n = 1.02 x 10⁻⁹/1.6 x 10⁻¹⁹

n = 63.75 x 10⁸ electrons

Learn more about electrons.

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