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jarptica [38.1K]
1 year ago
7

Estimate the solution to the following system of equations by graphing.

Mathematics
1 answer:
Mars2501 [29]1 year ago
4 0

Solution of 9x+8y=26 and 3x+2y=9 are given by \mathbf{x=\frac{10}{3},y=-\frac{1}{2}}.

We have to plot the graphs of the given two lines or curves, then we have to find the intersection point(s) of the curves or lines. That point is the solution for the system of the equations.

Given equations are,

9x+8y=26 .................(1)

3x+2y=9 ...................(2)

Now multiplying 3 with (2) and then subtracting (1) from that we get,

3(3x+2y)-(9x+8y)=3\times9-26\\\Rightarrow9x+6y-9x-8y=27-26\\\Rightarrow-2y=1\\\Rightarrow y=\frac{-1}{2}

Substituting the value of y in (1) we get,

9x+8\times\frac{-1}{2}=26\\\Rightarrow9x-4=26\\\Rightarrow9x=26+4\\\Rightarrow x=\frac{30}{9}=\frac{10}{3}

Also if we draw the graphs of the given equations by using graphing calculator we get,

Here in the graph we can see that the lines represented by the given equations intersects each other at point \left(\frac{10}{3},-\frac{1}{2}\right).

Hence the solution is x=\frac{10}{3},y=-\frac{1}{2}.

Learn more about System of equations here -

brainly.com/question/1365672

#SPJ10

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Inequality in real world.
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Solving real-world problems that involve inequalities is very much like solving problems that involve equations.

Example 1

In order to get a bonus this month, Leon must sell at least 120 newspaper subscriptions. He sold 85 subscriptions in the first three weeks of the month. How many subscriptions must Leon sell in the last week of the month?

Solution

Let x = the number of subscriptions Leon sells in the last week of the month. The total number of subscriptions for the month must be greater than 120, so we write :

85 + x ≥ 120.

We solve the inequality by subtracting 85 from both sides: x ≥ 35.

Leon must sell 35 or more subscriptions in the last week to get his bonus.

Check

To check the answer, we see that 85 + 35 = 120. If he sells 35 or more subscriptions, the total number of subscriptions he sells that month will be 120 or more. The answer checks out.

Example 2

Virenas Scout troop is trying to raise at least $650 this spring. How many boxes of cookies must they sell at $4.50 per box in order to reach their goal?

Solution

Let x = number of boxes sold. Then the inequality describing this problem is 4.50 ≥ 650.

We solve the inequality by dividing both sides by 4.50: x ≥ 144.44.

We round up the answer to 145 since only whole boxes can be sold.

Virenas troop must sell at least 145 boxes.

Check

If we multiply 145 by $4.50 we obtain $652.50, so if Virenas troop sells more than 145 boxes they will raise more than $650. But if they sell 144 boxes, they will only raise $648,

which is not enough. So they must indeed sell at least 145 boxes. The answer checks out.

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3 years ago
Khan academy!! Pls help will give brainllyest!!!
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Answer:

<u>C and D</u>

Step-by-step explanation:

<u>D.</u> A negative times a positive gives you a negative, so the first 2 fractions will still be negatives after they get out of the parenthesis

<u>C.</u> The 4/7 and -4/7 cancel out

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Answer:

First,

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(s+3)+ [(7s-2)+3] = 52 is the equation.

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