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Aloiza [94]
1 year ago
12

Which two types of waves can transmit energy through a vacuum?

Physics
1 answer:
diamong [38]1 year ago
7 0

Given what we know, we can confirm that amongst the wave types mentioned both X-rays and radio waves are able to transmit energy through a vacuum.

<h3>How can these waves propagate through a vacuum?</h3>

This is due to the fact that unlike sound, water, and seismic waves that transmit energy through air, water, or the earth, the waves mentioned above, those being radio and x-rays, do not need a medium through which to propagate. This allows them to exist and transmit energy even in a vacuum such as outer space, which is corroborated by their existence in space.

Therefore, we can confirm that amongst the wave types mentioned both X-rays and radio waves are able to transmit energy through a vacuum.

To learn more about waves visit:

brainly.com/question/3040658?referrer=searchResults

#SPJ1

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An object is moving at a velocity of 14 m/s. It accelerates to a velocity of 48 m/s over a time
Tju [1.3M]

Answer:

.

Explanation:

..

5 0
2 years ago
A helium balloon has a pressure of 40 psi at 20°C. What will the pressure be at 40°C? Assume constant volume and mass.
Likurg_2 [28]

Answer:

P V = N R T     ideal gas equation

P2 / P1 = T2 / T1       where the other variables are constant

P2 = (T2 / T1) * P1 = (313 / 293) * 40 psi = 42.7 psi

5 0
2 years ago
A 40-w lightbulb connected to a 120-v source experiences a voltage surge that produces 132 v for a moment. by what percentage do
andrey2020 [161]
R=U^2/P=120*120/40=360 ohm
P2=U2^2/R=132*132/360=48.4 w
power increase ratio (48.4-40)/40=21%
3 0
3 years ago
Two coulombs of charge pass through a wire in 5 seconds. Calculate the current in the wire. 1​
gogolik [260]

Answer:

0.4A.

Explanation:

Current (A) = Charge (coulomb)/Time (secs)

2 coulombs/5 secs = 0.4A

7 0
2 years ago
To make a given sound seem twice as loud, how should a musician change the intensity of the sound?
Serhud [2]

Answer:

C. Quadruple the intensity

Explanation:

The intensity of the sound is proportional to square of amplitude of the sound.

I ∝ A²

\frac{I_1}{A_1^2} = \frac{I_2}{A_2^2}\\\\I_2 = \frac{I_1A_2^2}{A_1^2}

When the given sound is twice loud as the initial value, then the new amplitude is twice the former.

A₂ = 2A₁

I_2 = \frac{I_1A_2^2}{A_1^2} \\\\I_2 = \frac{I_1(2A_1)^2}{A_1^2} \\\\I_2 = \frac{4I_1A_1^2}{A_1^2}\\\\ I_2 = 4I_1

Thus, to make a given sound seem twice as loud, the musician should Quadruple the intensity

3 0
3 years ago
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