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2 years ago

Rearranging the equation m= 5Kg and a= 2 m\s2

Physics

1 answer:

olganol [36]2 years ago

6 0

The force of the object with the given mass and acceleration is determined as 10 N.

<h3>Force of the object</h3>

The force of the given object is calculated from Newton's second law of motion as follows;

F = ma

where;

m is mass of the object = 5 kg
a is acceleration of the object = 2 m/s²

F = 5 x 2 = 10 N

Thus, the force of the object with the given mass and acceleration is determined as 10 N.

The complete question is below:

Rearranging the equation m = F/a and solve for F, m= 5Kg and a= 2 m\s2

Learn more about force here: brainly.com/question/12970081

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what is the energy required to melt down a 12,400g Gold bar assuming its temperature goes from 23c to 1,064c

sergejj [24]

1665183.6J

Explanation:

Given parameters:

Mass of Gold = 12400g

Initial temperature = 23°C

Final temperature = 1064°C

Unknown:

Energy required to melt = ?

Solution:

The amount of heat required to cause this temperature change to heat the gold bar is given as;

H = m c Ф

m is the mass of gold bar

c is the specific heat capacity of gold

Ф is the heat change

Specific heat capacity of gold = 0.129J/g°C

H = m c (Ф₂ - Ф₁)

H = 12400 x 0.129 x (1064 - 23) = 1665183.6J

learn more:

Specific heat capacity brainly.com/question/7210400

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5 0

3 years ago

What happens when a hydrogen atom acts like a nonmetal in a chemical reaction?

lord [1]

<span>It gains an electron.</span>

7 0

3 years ago

Please Help!!! I WILL GIVE BRAINLIEST!!!! An electron is in motion at 4.0 × 10^6 m/s horizontally when it enters a region of spa

dybincka [34]

Answer:

a. 9.52 cm b. 4.34 × 10⁶ m/s

Explanation:

a. The horizontal distance traveled by the electron when it hits the plate.

The electric force F on the electron due to the electric field E of mass, m is

F = -eE = ma

a = -eE/m where a = acceleration of electron

The vertical distance moved by the electron is given by

Δy = ut +1/2at²

u = initial vertical velocity = 0. and take the top plate as y = 0 and bottom plate as y

So,

0 - y = 0 × t + 1/2at²

-y = 1/2at²

substituting a = -eE/m

-y = 1/2(-eE/m)t²

y = eEt²/2m

making t subject of the formula,

t = √(2ym/eE) where t is the time it takes to reach the bottom plate.

Since E = 4.0 × 10² N/C, y = distance between plates = 2.0 cm = 0.02 m, m = 9.109 × 10⁻³¹kg and e = 1.602 × 10⁻¹⁹ C

t = √[(2 × 0.02 m × 9.109 × 10⁻³¹kg)/(1.602 × 10⁻¹⁹ C × 4.0 × 10² N/C)]

t = √[(0.36436 × 10⁻³¹kgm)/(6.408 × 10⁻¹⁷ N)]

t = √[(0.0569 × 10⁻¹⁴kgm/N)t

t = 0.238 × 10⁻⁷ s

t = 23.8 × 10⁻⁹ s

t = 23.8 ns

The horizontal distance moved when it hits the plates x = vt where v = initial horizontal velocity = 4.0 × 10⁶ m/s

x = 4.0 × 10⁶ m/s × 23.8 × 10⁻⁹ s

= 0.0952 m

= 9.52 cm

b. The velocity of the electron as it strikes the plate.

To find the velocity of the electron as it strikes the plates, we calculate its final vertical velocity V as it strikes the plate. This is gotten from

v' = u + at since u = 0,

v' = at

= -eEt/m

= -(1.602 × 10⁻¹⁹ C × 4.0 × 10² N/C × 0.238 × 10⁻⁷ s)/9.109 × 10⁻³¹kg

= -1.525 × 10⁻²⁴ Ns/9.109 × 10⁻³¹kg

= -0.167 × 10⁷ m/s

= -1.67 × 10⁶ m/s

So, the resultant velocity as it strikes the plate v = √(v'² + v²)

= √((-1.67 × 10⁶ m/s)² + (4 × 10⁶ m/s)²)

= √(2.7889 + 16) × 10⁶ m/s

= √18.7889 × 10⁶ m/s

= 4.335 × 10⁶ m/s

≅ 4.34 × 10⁶ m/s

6 0

4 years ago

A typical running track is an oval with 74-m-diameter half circles at each end. A runner going once around the track covers a di

nirvana33 [79]

Answer:

The acceleration towards the center will be $0.43\ m/s^2$

Explanation:

Given the running track is an oval shape, and the diameter of each half-circle is 74 meters.

Also, the runner took 1 minute and 40 seconds to complete 400 m one round of the track.

We need to find the acceleration towards the center.

First, we will find the speed.

$v=\frac{d}{t}$

Where $v$ is the speed.

$d$ is the distance covered by the rider that is 400 meters.

$t$ is the time taken by the rider to complete the lap which is 1 minute and 40 seconds. $(60\ s +40\ s) = 100$ seconds.

So,

$v=\frac{400}{100}=4\ m/s$

And

$a_c=\frac{v^2}{r}$

Where $a_c$ is the acceleration towards the center.

$r$ is the radius which will be the half of the diameter 74 meters.

Hence, the radius will be 37 meters.

$a_c=\frac{4^2}{37} \\a_c=\frac{16}{37}=0.43\ m/s^2$

So, the centripetal acceleration of the rider will be $0.43\ m/s^2$

4 0

3 years ago

A mass of 1 slug is suspended from a spring whose spring constant is 9 lb/ft. The mass is initially released from a point 1 foot

FromTheMoon [43]

Answer:

t = 5π/18 + 2nπ/3 or π/6 + 2nπ/3 where n is a natural number

Explanation:

To solve the problem/ we first write the differential equation governing the motion. So,

$m\frac{d^{2} x}{dt^{2} } = -kx \\ m\frac{d^{2} x}{dt^{2} } + kx = 0\\\frac{d^{2} x}{dt^{2} } + \frac{k}{m} x = 0$

with m = 1 slug and k = 9 lb/ft, the equation becomes

$\frac{d^{2} x}{dt^{2} } + \frac{9}{1} x = 0\\\frac{d^{2} x}{dt^{2} } + 9 x = 0$

The characteristic equation is

D² + 9 = 0

D = ±√-9 = ±3i

The general solution of the above equation is thus

x(t) = c₁cos3t + c₂sin3t

Now, our initial conditions are

x(0) = -1 ft and x'(0) = -√3 ft/s

differentiating x(t), we have

x'(t) = -3c₁sin3t + 3c₂cos3t

So,

x(0) = c₁cos(3 × 0) + c₂sin(3 × 0)

x(0) = c₁cos(0) + c₂sin(0)

x(0) = c₁ × (1) + c₂ × 0

x(0) = c₁ + 0

x(0) = c₁ = -1

Also,

x'(0) = -3c₁sin(3 × 0) + 3c₂cos(3 × 0)

x'(0) = -3c₁sin(0) + 3c₂cos(0)

x'(0) = -3c₁ × 0 + 3c₂ × 1

x'(0) = 0 + 3c₂

x'(0) = 3c₂ = -√3

c₂ = -√3/3

So,

x(t) = -cos3t - (√3/3)sin3t

Now, we convert x(t) into the form x(t) = Asin(ωt + Φ)

where A = √c₁² + c₂² = √[(-1)² + (-√3/3)²] = √(1 + 1/3) = √4/3 = 2/√3 = 2√3/3 and Ф = tan⁻¹(c₁/c₂) = tan⁻¹(-1/-√3/3) = tan⁻¹(3/√3) = tan⁻¹(√3) = π/3.

Since tanФ > 0, Ф is in the third quadrant. So, Ф = π/3 + π = 4π/3

x(t) = (2√3/3)sin(3t + 4π/3)

So, the velocity v(t) = x'(t) = (2√3)cos(3t + 4π/3)

We now find the times when v(t) = 3 ft/s

So (2√3)cos(3t + 4π/3) = 3

cos(3t + 4π/3) = 3/2√3

cos(3t + 4π/3) = √3/2

(3t + 4π/3) = cos⁻¹(√3/2)

3t + 4π/3 = ±π/6 + 2kπ where k is an integer

3t = ±π/6 + 2kπ - 4π/3

t = ±π/18 + 2kπ/3 - 4π/9

t = π/18 + 2kπ/3 - 4π/9 or -π/18 + 2kπ/3 - 4π/9

t = π/18 - 4π/9 + 2kπ/3 or -π/18 - 4π/9 + 2kπ/3

t = -7π/18 + 2kπ/3 or -π/2 + 2kπ/3

Since t is not less than 0, the values of k ≤ 0 are not included

So when k = 1,

t = 5π/18 and π/6. So,

t = 5π/18 + 2nπ/3 or π/6 + 2nπ/3 where n is a natural number

6 0

3 years ago