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leva [86]
3 years ago
5

What is the exact meaning of net force?

Physics
1 answer:
ZanzabumX [31]3 years ago
4 0
In science and physics net force is the mean or overall of all the forces acting on an object.
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Would the energy of the wave increase or decrease if the speed of the wave increases? Why?
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i hope this helps some

Explanation:

The time-averaged power of a sinusoidal wave is proportional to the square of the amplitude of the wave and the square of the angular frequency of the wave. This is true for most mechanical waves. If either the angular frequency or the amplitude of the wave were doubled, the power would increase by a factor of four.

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A train stops suddenly at the train station and everyone in the cars continue moving forward.
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How atoms are in one mole of patassuim
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When you lift an object by moving only your forearm, the main lifting muscle in your arm is the biceps. Suppose the mass of a fo
Sladkaya [172]

Answer:

The answers to the questions are;

The force the biceps must exert to hold a 850 g ball at the end of the forearm at distance dball = 34.0 cm from the elbow, with the forearm parallel to the floor is 166.77 N Upwards.

The force the elbow must  exert is 145.6785 N downwards.

Explanation:

We are required to analyze the system using the principle of moments as follows.

Mass of forearm = 1.30 kg

Weight of forearm = mass × acceleration due to gravity = 1.30 kg × 9.81  m/s²= 12.753 N

Location of point of action of weight of forearm = midpoint  17 cm

Forearm to biceps distance = 3.00 cm from the elbow.

Mass of the ball = 850 g

Weight of ball = mass × acceleration due  to gravity = 0.850 kg × 9.81 = 8.3385 N

Position of the ball = end of the forearm

Therefore, taking moment about the elbow, we have

∑Mₓ = 0, we take clockwise moment to be positive, therefore

8.3385 N× 34.0 cm + 12.753 N× 17 cm - F_{biceps}×3.00 cm = 0

Therefore F_{biceps}×3.00 cm = 500.31 N cm

Therefore F_{biceps} = (500.31 N·cm)/(3.00 cm) = 166.77 N Upwards

The force exerted by the elbow is given by,

Taking moment about the point of contact between the biceps and the forearm, we get

F_{elbow} × 3.00 cm = 8.3385 N× 31.0 cm + 12.753 N× 14 cm

F_{elbow} = 145.6785 N downwards.

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3 years ago
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