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masha68 [24]
2 years ago
5

The decomposition of ammonia to the elements is a first-order reaction with a half-life of 200 s at a certain temperature. How l

ong will it take the partial pressure of ammonia to decrease from 0.100 atm to 0.00625 atm?
Physics
1 answer:
Feliz [49]2 years ago
7 0

Based on the half-life of the reaction, time taken for the partial pressure of ammonia to decrease from 0.100 atm to 0.00625 atm is 800 seconds.

<h3>What is the half-life of a substance?</h3>

The half-life of a substance is the time taken for half the amount of atoms present in that substance to decay.

The half-life of the reaction is 200 seconds.

After, one half-life, pressure reduces to 0.0500 atm

After, two half-lives, pressure reduces to 0.0250 atm

After, three half-lives, pressure reduces to 0.01250 atm

After, four half-lives, pressure reduces to 0.00625 atm

Time taken = 4 * 200 = 800 seconds

Therefore, time taken for the partial pressure of ammonia to decrease from 0.100 atm to 0.00625 atm is 800 seconds.

Learn more about half-life at: brainly.com/question/26689704

#SPJ1

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Increasing its surface area

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A truck is moving 14m/s to the south. If it takes the truck 20 seconds to reduce its velocity to 10m/s south. What is is acceler
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4 years ago
22. What is the length of a pendulum that has a period of 0.500 s?
sergeinik [125]

6.21 cm

  • use the pendulum formula : \sf \bold{\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{L}}{\mathrm{g}}}}

where

  • T is time or period
  • π is pie = 22/7
  • L is pendulum length
  • g is acceleration due to gravity

Given:

  • T = 0.500 s
  • g = 9.8 m/s²

solving step-wise:

\dashrightarrow \mathrm{T}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{g}}}

\sf \dashrightarrow \mathrm{0.5}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}

\dashrightarrow \mathrm{\dfrac{0.5}{2 \pi } }=\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}

\dashrightarrow\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= \mathrm{\dfrac{0.5}{2 \pi } }

\sf \dashrightarrow{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2

\sf \dashrightarrow{{\mathrm{L}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2*9.8

\sf \dashrightarrow{{\mathrm{L}}=0.06205922 \ m

  • 1 m → 100 cm

\sf \dashrightarrow{{\mathrm{L}}=6.2059\ cm

\sf \dashrightarrow{{\mathrm{L}}=6.21\ cm             { rounded to nearest hundredth }

6 0
2 years ago
Read 2 more answers
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