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3 years ago

Identify a wave that speeds up when it passes from air to water as well as one that slows down

Physics

1 answer:

diamong [38]3 years ago

3 0

Answer:

A sound wave speeds up as it passes from air to water. A light wave slows down as it passes from air to water.

Explanation:

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What is 12 and 1 half % expressed as a fraction

kiruha [24]

12 1/2 i would assume

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3 years ago

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1. What is the potential energy of a 4-kilogram potted plant that is on a 1 meter-high plant

Yuri [45]

39.2 J

Explanation:

Step 1:

To find the potential energy the following formula is used.

Potential Energy = m × g × h

Where,

m = Mass

g = Acceleration due to gravity

h = Height

Step 2:

Here m = 4 kg, g = 9.8 m/s², h = 1 m

Potential Energy = ( 4 × 9.8 × 1)

= 39.2 J

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3 years ago

1.How long dose long term alcohol abuse affect the liver ?

Agata [3.3K]

1. B- it can cause cirrhosis
2. C- intoxication
3. A- admit to having a problem with alcohol
4. D- binge-drinking
5. A- depressant
6. true
7. false

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3 years ago

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A powerful motorcycle can produce an acceleration of 3.00 m/s2 while traveling at 106.0 km/h. At that speed, the forces resistin

otez555 [7]

Answer:

"1155 N" is the appropriate solution.

Explanation:

Given:

Acceleration,

$a=3 \ m/s^2$

Forces resisting motion,

$F_f=432 \ N$

Mass,

$m = 241 \ kg$

By using Newton's second law, we get

⇒ $F-F_f=ma$

Or,

⇒ $F=ma+F_f$

By putting the values, we get

⇒ $=(3\times 241)+432$

⇒ $=723+432$

⇒ $=1155 \ N$

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3 years ago

An artificial satellite is in a circular orbit around a planet of radius r= 2.05 x103 km at a distance d 310.0 km from the plane

lubasha [3.4K]

Answer:

$\rho = 12580.7 kg/m^3$

Explanation:

As we know that the satellite revolves around the planet then the centripetal force for the satellite is due to gravitational attraction force of the planet

So here we will have

$F = \frac{GMm}{(r + h)^2}$

here we have

$F =\frac {mv^2}{(r+ h)}$

$\frac{mv^2}{r + h} = \frac{GMm}{(r + h)^2}$

here we have

$v = \sqrt{\frac{GM}{(r + h)}}$

now we can find time period as

$T = \frac{2\pi (r + h)}{v}$

$T = \frac{2\pi (2.05 \times 10^6 + 310 \times 10^3)}{\sqrt{\frac{GM}{(r + h)}}}$

$1.15 \times 3600 = \frac{2\pi (2.05 \times 10^6 + 310 \times 10^3)}{\sqrt{\frac{(6.67 \times 10^{-11})(M)}{(2.05 \times 10^6 + 310 \times 10^3)}}}$

$M = 4.54 \times 10^{23} kg$

Now the density is given as

$\rho = \frac{M}{\frac{4}{3}\pi r^3}$

$\rho = \frac{4.54 \times 10^{23}}{\frac{4}[3}\pi(2.05 \times 10^6)^3}$

$\rho = 12580.7 kg/m^3$

8 0

3 years ago