Answer:
Tc = = 424.85 K
Explanation:
Data given:
D = 60 mm = 0.06 m

k = 50 w/m . k
c = 500 j/kg.k





HEAT FLOW Q is


= 47123.88 w per unit length of rod
volumetric heat rate





= 424.85 K
Answer:
The initial temperature will be "385.1°K" as well as final will be "128.3°K".
Explanation:
The given values are:
Helium's initial volume, v₁ = 6 m³
Mass, m = 1.5 kg
Final volume, v₂ = 2 m³
Pressure, P = 200 kPa
As we know,
Work, 
On putting the estimated values, we get
⇒ 
⇒ 
⇒ 
Now,
Gas ideal equation will be:
⇒ 
On putting the values. we get
⇒ 
⇒ 
⇒
(Initial temperature of helium)
and,
⇒ 
On putting the values, we get
⇒ 
⇒ 
⇒
(Final temperature of helium)
The person that is correct as regards statement made about stoichiometric ratio is; <em><u>Tech B</u></em>
In air-fuel mixture, when there is a mix air and fuel in the ideal amounts to make an engine to run efficiently,the ideal ratio of air to fuel is known Stoichiometric ratio.
This stoichiometric ratio is the comparison between the weight of the air relative to the weight of the fuel that it has been mixed with.
Now, weight is in lb and as such, tech B is correct because his ratio is 14.7lb to 1 lb.
Read more at; brainly.com/question/16971089
Answer:
repair of inverters and anything that has to do with solar energy...that is power from the sun
Answer:
hL = 0.9627 m
Explanation:
Given
Q = 0.040 m³/s (constant value)
D₁ = 15 cm = 0.15 m ⇒ R₁ = D₁/2 = 0.15 m/2 = 0.075 m
D₂ = 8 cm = 0.08 m ⇒ R₂ = D₂/2 = 0.08 m/2 = 0.04 m
P₁ = 480 kPa = 480*10³Pa
P₂ = 440 kPa = 440*10³Pa
α = 1.05
ρ = 1000 Kg/m³
g = 9.81 m/s²
h₁ = h₂
hL = ? (the irreversible head loss in the reducer)
Using the formula Q = v*A ⇒ v = Q/A
we can find the velocities v₁ and v₂ as follows
v₁ = Q/A₁ = Q/(π*R₁²) = (0.040 m³/s)/(π*(0.075 m)²) = 2.2635 m/s
v₂ = Q/A₂ = Q/(π*R₂²) = (0.040 m³/s)/(π*(0.04 m)²) = 7.9577 m/s
Then we apply the Bernoulli law (for an incompressible flow)
(P₂/(ρ*g)) + (α*v₂²/(2*g)) + h₂ = (P₁/(ρ*g)) + (α*v₁²/(2*g)) + h₁ - hL
Since h₁ = h₂ we obtain
(P₂/(ρ*g)) + (α*v₂²/(2*g)) = (P₁/(ρ*g)) + (α*v₁²/(2*g)) - hL
⇒ hL = ((P₁-P₂)/(ρ*g)) + (α/(2*g))*(v₁²-v₂²)
⇒ hL = ((480*10³Pa-440*10³Pa)/(1000 Kg/m³*9.81 m/s²)) + (1.05/(2*9.81 m/s²))*((2.2635 m/s)²-(7.9577 m/s)²)
⇒ hL = 0.9627 m