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Masja [62]
3 years ago
10

An engineer lives in Hawaii at a location where the annual rain fall is 300 inches. She decides to use the rain to generate elec

tricity. She places a rain barrel in a tree at a height of 100 ft. If the volumetric flow rate of water in the system is 3.6x10-6 ft3 /s, what is the average rate that power that could be generated in one year (in lbf-ft/hr)? [Ws= 80.7 lbfft/hr]
Engineering
1 answer:
Alex777 [14]3 years ago
4 0

Answer:

80.7lbft/hr

Explanation:

Flow rate of water in the system = 3.6x10^-6

The height h = 100

1s = 1/3600h

This implies that

Q = 3.6x10^-6/[1/3600]

Q = 0.0000036/0.000278

Q = 0.01295

Then the power is given as

P = rQh

The specific weight of water = 62.3 lb/ft³

P = 62.3 x 0.01295 x 100

P = 80.675lbft/h

When approximated

P = 80.7 lbft/h

This is the average power that could be generated in a year.

This answers the question and also corresponds with the answer in the question.

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Answer:

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From equilibrium of block, N = W = mg

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m_a•v_a1 + m_b•v_b1 = m_a•v_a2 + m_b•v_b2

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15(8.744) + 10(0) = 15(v_a2) + 10(v_b2)

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Coefficient of restitution has a formula;

e = (v_b2 - v_a2)/(v_a1 - v_b1)

From the question, e = 0.6.

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0.6 x 8.744 = (v_b2 - v_a2)

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T1 + V1 = T2 + V2

Thus,

(1/2)m_b•(v_b2)² + (1/2)k(s_1)² = (1/2)m_b•(v_b'2)² + (1/2)k(s_max)²

(1/2)10•(8.394)² + (1/2)1000(0)² = (1/2)10•(0)² + (1/2)(1000)(s_max)²

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