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fomenos
3 years ago
5

All the members of this family (inner transition metals) are both ______________ and _____________.

Chemistry
2 answers:
Annette [7]3 years ago
6 0
The antinides and the lanthanide’s.
avanturin [10]3 years ago
3 0

Answer:

The actinides and the lanthanides

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I wanted known how many of the reaction below is energy released
Tema [17]

Answer:

2

Explanation:

In two reactions energy is released.

1) C₆H₁₂O₆ + 6O₂    →    6H₂O + 6CO₂ + heat

It is cellular respiration reaction.It involves the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.

Glucose + oxygen → carbon dioxide + water + 38ATP

2) 2H₂ + O₂   →    2H₂O  ΔH = -486 kj/mol

The given reaction is formation of water. In this reaction oxygen and hydrogen react to form water and 486 kj/mol is also released.

The reaction in which heat is released is called exothermic reaction.

Exothermic reaction:

The type of reactions in which energy is released are called exothermic reactions.

In this type of reaction energy needed to break the bonds are less than the energy released during the bond formation.

For example:

Chemical equation:

C + O₂   →  CO₂

ΔH = -393 Kj/mol

it can be written as,

C + O₂   →  CO₂ + 393 Kj/mol

Endothermic reactions:

The type of reactions in which energy is absorbed are called endothermic reactions.

In this type of reaction energy needed to break the bond are higher than the energy released during bond formation.

For example:

C + H₂O   →  CO  + H₂

ΔH = +131 kj/mol

it can be written as,

C +  H₂O  + 131 kj/mol  →  CO  + H₂

5 0
3 years ago
Please help fast. I will give brainliest.
Sonbull [250]

Answer:39 min

Explanation:

5 0
2 years ago
At the beginning of an experiment, a scientist has 176 grams of radioactive goo. After 165 minutes, her sample has decayed to 5.
Paul [167]
The half-life equation is written as:

An = Aoe^-kt

We use this equation for the solution. We do as follows:

5.5 = 176e^-k(165)
k = 0.02
<span>What is the half-life of the goo in minutes? 
</span>
0.5 = e^-0.02t
t = 34.66 minutes <----HALF-LIFE


Find a formula for G(t) , the amount of goo remaining at time t.G(t)=? 

G(t) = 176e^-0.02t

How many grams of goo will remain after 50 minutes? 

G(t) = 176e^-0.02(50) = 64.75 g
6 0
3 years ago
There are 154,000 mg of sugar in a
Kipish [7]

Explanation:

1g = 1000mg

154000mg = 154g

No of days she can drink = 154÷ 11 = 14days

5 0
3 years ago
A sub-shell with n = 6, l = 2 can accommodate a maximum of:
Mrrafil [7]

Answer:

72

Explanation:

2n^2

n=6

2(6)^2=2×36

=72

8 0
3 years ago
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