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fomenos
2 years ago
5

All the members of this family (inner transition metals) are both ______________ and _____________.

Chemistry
2 answers:
Annette [7]2 years ago
6 0
The antinides and the lanthanide’s.
avanturin [10]2 years ago
3 0

Answer:

The actinides and the lanthanides

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You carefully weigh out 11.00 g of caco3 powder and add it to 44.55 g of hcl solution. you notice bubbles as a reaction takes pl
Zinaida [17]
The bubbles that were observed after the mixing of the two substances is one of the products of the reaction. It is the carbon dioxide that is produced. To determine the mass of this gas produced, we need to remember the Law of conservation of mass where mass cannot be created or destroyed. With this, we can say that the total mass that goes in a process should be equal to the mass that is goes out of the process no matter what the reaction is. We do as follows:

Mass of reactants = mass of products
11.00 + 44.55 = 51.04 + mass of carbon dioxide
mass of carbon dioxide = 4.51 g
8 0
3 years ago
Jean and her mother were taking a walk when they saw the two rocky outcrops in the diagram below.
Veseljchak [2.6K]

Answer:

you have to attach the diagram

Explanation:

5 0
2 years ago
What occurs in order to break the bond in a Cl2 molecule?
alukav5142 [94]
The bond between the 2 Cl atoms in a Cl₂ molecule is a covalent bond. 
to break this covalent bond, energy is required. 
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therefore to break the covalent bond in Cl₂ molecule 
1)energy is absorbed
3 0
3 years ago
Read 2 more answers
When NADH donates two electrons to ubiquinone during respiration, ubiquinone isa. reduced.b. oxidized.c. phosphorylated.d. aerob
olga nikolaevna [1]
Reduced ... more electrons gain is a reduction
5 0
3 years ago
Concentrated hydrochloric acid, HCl, comes with an approximate molar concentration of 12.1 M. If you are instructed to prepare 3
Semmy [17]

Answer:

28.20 mL of the stock solution.

Explanation:

Data obtained from the question include the following:

Molarity of stock solution (M1) = 12.1 M

Volume of diluted solution (V2) = 350.0 mL

Molarity of diluted solution (M2) = 0.975 M

Volume of stock solution needed (V1) =..?

The volume of stock solution needed can be obtained by using the dilution formula as shown below:

M1V1 = M2V2

12.1 x V1 = 0.975 x 350

Divide both side by 12.1

V1 = (0.975 x 350)/12.1

V1 = 28.20 mL.

Therefore, 28.20 mL of the stock solution will be needed to prepare 350.0 mL of 0.975 M HCl solution.

6 0
3 years ago
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