Answer:
There are two major categories of energy: renewable and non-renewable.
Non-renewable energy resources are available in limited supplies, usually because they take a long time to replenish. The advantage of these non-renewable resources is that power plants that use them are able to produce more power on demand. The non-renewable energy resources are:
Renewable resources, on the other hand, replenish themselves. The five major renewable energy resources are:
- Biomass, or organic material from plants and animals
- Geothermal, which is naturally occurring heat from the earth
While renewable energy resources have the advantage of unlimited supply over the long haul, they are limited in their availability at any given moment.
For example, the sun rises each day, but its ability to generate power is limited when its cloudy. Another disadvantage is that power plant operators can’t crank up renewable energy production when people are consuming more power, such as on a hot day when many people are running air conditioners at the same time.
I think the answer is Reflected, but I may be wrong.
Answer : The concentration of copper(II) fluoride in the solution is, 
Explanation : Given,
Moles of copper(II) fluoride = 0.032 μ
mol = 
conversion used : 
Volume of solution = 500 mL
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
Now put all the given values in this formula, we get:
Therefore, the concentration of copper(II) fluoride in the solution is,
Answer:
Volume in L = 0.50 L
Explanation:
Given data:
Molarity of solution = 0.1850 M
Mass of BaCl₂ = 19.30 g
Volume of solution = ?
Solution:
First of all we will calculate the number of moles of solute:
Number of moles = mass/molar mass
Molar mass of BaCl₂ = 208.23 g/mol
Number of moles = 19.30 g / 208.23 g/mol
Number of moles = 0.093 mol
Volume of solution:
Molarity = number of moles of solute / volume of solution in L
0.1850 M = 0.093 mol / Volume in L
Volume in L = 0.093 mol / 0.1850 M (M= mol/L)
Volume in L = 0.50 L
