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masha68 [24]
3 years ago
13

A 44.6 mg sample of carbon reacts with sulfur to form 124 mg of the compound. part a what is the empirical formula of the carbon

sulfide?
Chemistry
1 answer:
Inga [223]3 years ago
4 0

The empirical formula of carbon sulfide = C3S2

calculation

calculate the mass of S used = 124-44.6= 79.4 grams

find the moles of each element

that is carbon(C)= 44.6/12= 3.717 moles    

          sulfur (S) = 79.4/32= 2.48 moles

find the mole ratio by dividing each mole with the smallest mole( 2.48)

that is carbon = 3.717/2.48 = 1.5

        sulfur = 2.48/2.48= 1

multiply by 2 to remove the decimal

= C=1.5 x2=3

S= 1/2 =2

therefore the empirical formula = C3S2

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90 minutes x 1 hour / 60 minutes = 1.5 hours

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Can someone please help me with this?
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Answer:

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Explanation:

4 0
3 years ago
a chemist dissolves 0.564 moles of manganese (IV) oxide (MnO2) in water, and adds enough water to make 0.510 L of solution. Calc
ladessa [460]

Answer:

The molarity of the solution is 1.1 \frac{moles}{liter}

Explanation:

Molarity is a measure of the concentration of that substance that is defined as the number of moles of solute divided by the volume of the solution.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

molarity=\frac{number of moles of solute}{volume}

Molarity is expressed in units \frac{moles}{liter}

In this case

  • number of moles of solute= 0.564 moles
  • volume= 0.510 L

Replacing:

molarity=\frac{0.564 moles}{0.510 L}

Solving:

molarity= 1.1 \frac{moles}{liter}

<u><em>The molarity of the solution is 1.1 </em></u>\frac{moles}{liter}<u><em></em></u>

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3 years ago
1 kg of water (specific heat = 4184 J/(kg K)) is heated from freezing (0°C) to boiling (100°C). What is the change in thermal en
Andrews [41]

Answer: 1560632 joules

Explanation:

The change in thermal energy (Q) required to heat ice depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = ?

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C = 4184 J/(kg K)

Φ = (Final temperature - Initial temperature)

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(100°C + 273) = 373K

Then, Q = MCΦ

Q = 1kg x 4184 J/(kg K) x 373K

Q = 1560632 joules

Thus, the change in thermal energy is 1560632 joules

5 0
4 years ago
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