A 44.6 mg sample of carbon reacts with sulfur to form 124 mg of the compound. part a what is the empirical formula of the carbon
1 answer:
You might be interested in
<u>Answer:</u> The concentration of in the cell is
<u>Explanation:</u>
We are given:
<u>Oxidation half reaction:</u>
<u>Reduction half reaction:</u>
The substance having highest positive potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.
Here, tin will undergo reduction reaction and will get reduced.
Oxidation reaction occurs at anode and reduction reaction occurs at cathode.
To calculate the of the reaction, we use the equation:
Putting values in above equation, we get:
To calculate the EMF of the cell, we use the Nernst equation, which is:
where,
= electrode potential of the cell = 0.660 V
= standard electrode potential of the cell = +0.624 V
n = number of electrons exchanged = 2
= ?
Putting values in above equation, we get:
Hence, the concentration of ions is