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Crazy boy [7]
2 years ago
15

Rcise 5

Physics
1 answer:
DochEvi [55]2 years ago
5 0

The acceleration of the train at the give initial and final velocity is determined as 10.5 m/s².

<h3>Acceleration of the train</h3>

The acceleration of the train is calculated as follows;

a = Δv/t

where;

  • u is initial velocity = 162 km/hr = 45 m/s
  • v is final velocity of the car = 540 km/hr = 150 m/s

a = (150 - 45)/10

a = 10.5 m/s²

Thus, the acceleration of the train at the give initial and final velocity is determined as 10.5 m/s².

Learn more about acceleration here: brainly.com/question/605631

#SPJ1

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3 years ago
1.) A ski jump is angled at 40° and the skier is launched at 25 m/s. A.) What was her highest
prohojiy [21]

A) 13.2 m

The motion of the skier is a projectile motion, which consists of two independent motions:

- a horizontal motion with constant speed

- a vertical motion with constant acceleration g=-9.8 m/s^2 (acceleration of gravity) downward

To find the maximum height of her trajectory, we are only concerned with her vertical motion.

The initial vertical velocity upward is

u_y = u_0 sin \theta = (25) sin 40^{\circ} =16.1 m/s

then we can use the following SUVAT equation:

v_y^2 - u_y^2 = 2ah

where

v_y=0 is the final vertical velocity, which is zero at the maximum height

u_y = 16.1 m/s is the initial vertical velocity

a=g=-9.8 m/s^2

h is the maximum height

Solving for h,

h=\frac{v_y^2-u_y^2}{2g}=\frac{-(16.1)^2}{2(-9.8)}=13.2 m

B) 1.64 s

The time needed to reach the highest point can be found by analyzing again the vertical motion only. In fact, we can use the  following SUVAT equation:

v_y = u_y +at

where

u_y = 16.1 m/s

a=g=-9.8 m/s^2

At the maximum height, the vertical velocity is zero:

v_y=0

So we can solve the equation to find the corresponding time:

t=\frac{v_y-u_y}{a}=\frac{0-16.1}{-9.8}=1.64 s

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