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Doss [256]
2 years ago
13

What're three main orbital overlapping?​

Chemistry
2 answers:
professor190 [17]2 years ago
3 0

Answer:

In the case of s and p orbitals, there can be three types of overlap. s – s orbital overlap (formation of H2 molecule): The mutual overlap between the half-filled s orbitals of two atoms is called s – s overlap and the covalent bond formed is known as sigma (s) bond. e.g. formation of a hydrogen molecule from two hydrogen atoms.

Explanation:

Sloan [31]2 years ago
3 0

Answer:

When two metal atoms are bonded together, a third type of bond, a delta bond, is possible.

Explanation:

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Which elements have only one electron orbit or shell? A. hydrogen (H) and helium (He) B. helium (He) and lithium (Li) C. krypton
mixer [17]

2.1 Electrons, Protons, Neutrons, and Atoms

Hydrogen H 1

Helium He 2

Lithium Li 3

Beryllium Be 4

5 0
4 years ago
Did diagram shows embryo development of four different animals. How is this evidence used to suggest that life changes over time
wel
It suggests that life changes over time by showing different animals at different stages in their life, also giving more than one example on how they can change during early development and throughout their lives
5 0
4 years ago
Read 2 more answers
2Pb(s) + O2(aq) + 4H+(aq) → 2H2O(l) + 2Pb2+(aq)
defon

Answer:

The answer to your question is 0.269 g of Pb

Explanation:

Data

Lead solution = 0.000013 M

Volume = 100 L

mass = 0.269 g

atomic mass Pb = 207.2 g

Chemical reaction

                        2Pb(s) + O₂(aq) + 4H⁺(aq) → 2H₂O(l) + 2Pb₂⁺(aq)

Process

1.- Calculate the mass of Pb in solution

Formula

Molarity = \frac{number of moles}{volume}

Solve for number of moles

Number of moles = Volume x Molarity

Substitution

Number of moles = 100 x 0.000013

Number of moles = 0.0013

2.- Calculate the mass of Pb formed.

                       207.2 g of Pb ----------------- 1 mol

                             x g             ----------------- 0.0013 moles

                        x = (0.0013 x 207.2) / 1

                        x = 0.269 g of Pb                                                                

8 0
4 years ago
Read 2 more answers
Why dont we include the mass of an atoms electrons in the atomic mass?
Oxana [17]
<span>Because protons and neutrons are so much more massive than electrons, almost all of the atomic mass in any atom comes from the nucleus, which contains all of the neutrons and protons.</span>
7 0
3 years ago
Indicate whether the following balanced equations involve oxidation-reduction. Check all that apply. Check all that apply. 2H2SO
guapka [62]

Answer :  The balanced equations involve oxidation-reduction are:

(a) 2H_2SO_4(aq)+2NaBr(s)\rightarrow Br_2(l)+SO_2(g)+Na_2SO_4(aq)+2H_2O(l)

(b) 3SO_2(g)+2HNO_3(aq)+2H_2O(l)\rightarrow 3H_2SO_4(aq)+2NO(g)

(c) NaI(aq)+3HOCl(aq)\rightarrow NaIO_3(aq)+3HCl(aq)

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

(a) The given chemical reaction is:

2H_2SO_4(aq)+2NaBr(s)\rightarrow Br_2(l)+SO_2(g)+Na_2SO_4(aq)+2H_2O(l)

This reaction involve oxidation-reduction reaction because the oxidation state bromine changes from (-1) to (0) which shows oxidation and sulfur changes from (+6) to (+4) which shows reduction.

(b) The given chemical reaction is:

3SO_2(g)+2HNO_3(aq)+2H_2O(l)\rightarrow 3H_2SO_4(aq)+2NO(g)

This reaction involve oxidation-reduction reaction because the oxidation state sulfur changes from (+4) to (+6) which shows oxidation and nitrogen changes from (+5) to (+2) which shows reduction.

(c) The given chemical reaction is:

NaI(aq)+3HOCl(aq)\rightarrow NaIO_3(aq)+3HCl(aq)

This reaction involve oxidation-reduction reaction because the oxidation state iodine changes from (-1) to (+5) which shows oxidation and chlorine changes from (+5) to (-1) which shows reduction.

(d) The given chemical reaction is:

PBr_3(l)+3H_2O(l)\rightarrow H_3PO_3(aq)+3HBr(aq)

This reaction does not involve oxidation-reduction reaction because the oxidation state of element present on reactant and product side are same.

3 0
3 years ago
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