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g100num [7]
3 years ago
9

Which change will always result in an increase in gravitational force between two objects

Physics
2 answers:
grin007 [14]3 years ago
7 0
Increasing the masses of the objects and decreasing the distance between the objects
jolli1 [7]3 years ago
5 0

Answer: Hello, the gravitational force has the form F = G \frac{M1*M2}{r^{2} }, where M1 and M2 are the masses of the objects, G is a constant and r is the distance between the two objects.

first: increasing the mass of the objects, the masses are in the numerator, then if whe increase either M1 or M2 (or both of them) then the gravitational force will increase.

second: decreasing the distance between the objects ( r in this case). r is in the denominator, si if r is smaller, the result of the division will be bigger, so if r decrease, then the gravitational force increase.

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Aleks04 [339]

(a) Let v be the maximum linear speed with which the ball can move in a circle without breaking the cord. Its centripetal/radial acceleration has magnitude

a_{\rm rad} = \dfrac{v^2}R

where R is the radius of the circle.

The tension in the cord is what makes the ball move in its plane. By Newton's second law, the maximum net force on it is

F = (1.500\,\mathrm{kg}) a_{\rm rad}

so that

(1.500\,\mathrm{kg}) \dfrac{v^2}{1.50\,\rm m} = 64.0\,\mathrm N

Solve for v :

v^2 = \dfrac{(64.0\,\mathrm N)(1.50\,\mathrm m)}{1.500\,\rm kg} \\\\ \implies \boxed{v = 8.00 \dfrac{\rm m}{\rm s}}

(b) The net force equation in part (a) leads us to the relation

F = \dfrac{mv^2}R \implies v = \sqrt{\dfrac{FR}m}

so that v is directly proportional to the square root of R. As the radius R increases, the maximum linear speed v will also increase, so the cord is less likely to break if we keep up the same speed.

6 0
1 year ago
What is one way you are using nonrenewable resources?
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Putting gas in your car is one way you are using non-renewable resources.

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3 years ago
1. Bone has a Young’s modulus of about
Blababa [14]

#1

As we know that

Y = \frac{stress}{strain}

now plug in all data into this

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strain = 9.33 \times 10^{-3}

now from the formula of strain

strain = \frac{\Delta L}{L}

9.33 \times 10^{-3} = \frac{\Delta L}{0.54}

\Delta L = 5.04 \times 10^{-3} m

\Delta L = 5.04 mm

#2

As we know that

pressure * area = Force

here we know that

Area = 3.53 \times 11.6 = 40.95 m^2

P = 0.2 atm = 0.2 \times 1.01 \times 10^5 = 2.02\times 10^4 Pa

now force is given as

F = 40.95 \times (2.02\times 10^4) = 8.27 \times 10^5 N

#3

As we know that density of water will vary with the height as given below

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here we know that

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#4

as we know that pressure changes with depth as per following equation

P = P_o + \rho g h

here we know that

P = 3 P_0

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2P_0 = \rho g h

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h = 20.1 m

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Here net buoyancy force due to water and oil will balance the weight of the block

so here we will have

mg = \rho_1V_1g + \rho_2V_2g

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x = 3.48 cm

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