When we move across a period from left to right then there will occur an increase in electronegativity and also there will occur an increase in non-metallic character of the elements.

As sulfur (S) is a group 16 element and chlorine (Cl) is a group 17 element. Hence, sulfur (S) is more metallic in nature than chlorine.

This means that chlorine (S) is less metallic than chlorine (Cl).

Both indium (I) and aluminium (Al) are group 13 elements. And, when we move down a group then there occur an increase in non-metallic character of the elements. As indium belongs to group 13 and period 5 whereas aluminium belongs to group 13 and period 3.

Therefore, aluminium (Al) is more metallic than indium (In).

Arsenic (Ar) is a group 15 element and bromine (Br) is a group 17 element. Therefore, arsenic is more metallic than bromine.

4 0

3 years ago

Help me please omg

Sever21 [200]

Answer:

NH₃

M = n/V(L)

0.844 mol (Both numbers have 3 significant figures so the result has 3 significant figures as well)

Explanation:

Step 1: Given and required data

Volume of solution (V): 375. mL

Molar concentration of the solution (M): 2.25 M

Chemical formula for ammonia: NH₃

Step 2: Calculate the moles (n) of ammonia (solute)

Molarity is equal to the moles of solute divided by the liters of solution.

M = n/V(L)

n = M × V(L)

n = 2.25 mol/L × 0.375 L = 0.844 mol (Both numbers have 3 significant figures so the result has 3 significant figures as well)

4 0

2 years ago