it is more dense think about how heavy the water feels you go down you feel more pressure so it is denser
The mass number is protons and neutrons. So I think it’s false
Answer:
An input of heat energy Yr don't you know stupied
<u>Answer:</u> The value of equilibrium constant for the given reaction at 517 K is 1.30
<u>Explanation:</u>
The chemical equation for the dissociation of
follows:
![2CH_2Cl_2(g)\rightleftharpoons CH_4(g)+CCl_4(g)](https://tex.z-dn.net/?f=2CH_2Cl_2%28g%29%5Crightleftharpoons%20CH_4%28g%29%2BCCl_4%28g%29)
The expression of
for above equation follows:
![K_{eq}=\frac{[CH_4][CCl_4]}{[CH_2Cl_2]^2}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BCH_4%5D%5BCCl_4%5D%7D%7B%5BCH_2Cl_2%5D%5E2%7D)
We are given:
![[CH_4]_{eq}=3.69\times 10^{-2}M](https://tex.z-dn.net/?f=%5BCH_4%5D_%7Beq%7D%3D3.69%5Ctimes%2010%5E%7B-2%7DM)
![[CCl_4]_{eq}=4.12\times 10^{-2}M](https://tex.z-dn.net/?f=%5BCCl_4%5D_%7Beq%7D%3D4.12%5Ctimes%2010%5E%7B-2%7DM)
![[CH_2Cl_2]_{eq}=3.42\times 10^{-2}M](https://tex.z-dn.net/?f=%5BCH_2Cl_2%5D_%7Beq%7D%3D3.42%5Ctimes%2010%5E%7B-2%7DM)
Putting values in above expression, we get:
![K_{eq}=\frac{(3.69\times 10^{-2})\times (4.12\times 10^{-2})}{(3.42\times 10^{-2})^2}\\\\K_{eq}=1.30](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%283.69%5Ctimes%2010%5E%7B-2%7D%29%5Ctimes%20%284.12%5Ctimes%2010%5E%7B-2%7D%29%7D%7B%283.42%5Ctimes%2010%5E%7B-2%7D%29%5E2%7D%5C%5C%5C%5CK_%7Beq%7D%3D1.30)
Hence, the value of equilibrium constant for the given reaction at 517 K is 1.30
<em>If heat is absorbed, the temperature increases. </em>
<em> If heat is released, the temperature decreases. </em>
<em>Hope I helped. :) </em>