Answer:
A) 31.22
Explanation:
The reaction of sulfuric acid with NaOH is:
H₂SO₄ + 2 NaOH → Na₂SO₄ + 2H₂O
To solve this problem we need to determine the moles of acid that will react, and, using the chemical equation we can determine the moles of NaOH and the volume that a 0.2389M NaOH solution would require to neutralize it.
<em>Moles H₂SO₄ (Molar mass: 98.08g/mol):</em>
0.9368g * 39.04% = 0.3657g H₂SO₄ * (1mol / 98.08g) =
3.7289x10⁻³moles H₂SO₄
And moles of NaOH that you require to neutralize the acid are:
3.7289x10⁻³moles H₂SO₄ * (2 moles NaOH / 1 mole H₂SO₄) =
7.4578x10⁻³ moles NaOH
Using a 0.2389M NaOH solution:
7.4578x10⁻³ moles NaOH * (1L / 0.2389mol) = 0.03122L = 31.22mL
Right answer is:
<h3>A) 31.22
</h3>
Caesium -bluish(Latin) Chlorine -yellow/green (Greek) Iodine -violet (Greek) <span>Rhodium -rose (Greek) Sulphur - yellow (Arabic)</span>
The correct answer is B... the should be divided into these to groups.
solid or liquid
Surface runoff, its quite obvious in the picture
Answer:
7.14%
Explanation:
From the question,
percentage by mass hydrogen in C₄H₈O₃ (h) = mass of hydrogen present in C₄H₈O₃(m)/molar mass of C₄H₈O₃ (m')
h = (m'/m)×100..................... Equation 1
Given: m' = (14×4)+(1×8)+(16×3) = 56+8+48 = 112 g, m = (1×8) = 8 g
Substitute these values into equation 1
h = (8/112)×100
h = 7.14%.
Hence the percentage of hydrogen in 70 g of C₄H₈O₃ is 7.14%