To solve the problem it is necessary to take into account the concepts related to simple pendulum, i.e., a point mass that is suspended from a weightless string. Such a pendulum moves in a harmonic motion -the oscillations repeat regularly, and kineticenergy is transformed into potntial energy and vice versa.
In the given problem half of the period is equivalent to 1 second so the pendulum period is,
From the equations describing the period of a simple pendulum you have to
Where
g= gravity
L = Length
T = Period
Re-arrange to find L we have
Replacing the values,
In the case of the reduction of gravity because the pendulum is in another celestial body, as the moon for example would happen that,
In this way preserving the same length of the rope but decreasing the gravity the Period would increase considerably.
Answer:
If both the maximum voltage and current are exceeded in a resistor, that the point will lie in the thermal breakdown of the resistor.
Explanation:
This indicated that there will be an abundance of free electrons which will be available freely. This abundance of the electrons in a conductor, will result in the reduction of the overall conductivity. whereas in an insulator or semiconductor this will enhance the overall conductivity.
As the point lies in the thermal breakdown, the Ohm's law is no longer valid and thus no analytical solution can be presented in this regard.
Answer:
16.26 cm in front of the mirror
Explanation:
Using,
1/f = 1/u+1/v....................... Equation 1
Where f = focal focal length of the concave mirror, u = object distance, v = image distance.
make v the subject of the equation
v = fu/(u-f)................... Equation 2
Note: The focal length of a concave mirror is positive
Using the real- is- positive convention
Given: f = 22/2 = 11 cm, u = 34 cm.
Substitute into equation 2
v = (34×11)/(34-11)
v = 374/23
v = 16.26 cm.
The image will be formed 16.26 cm in front of the mirror.
Answer:
Distance per unit time
Explanation:
Speed is the rate at which someone or something is able to move or operate.
