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ZanzabumX [31]
4 years ago
9

Two speakers, one directly behind the other, are each generating a 280-Hz sound wave. What is the smallest separation distance b

etween the speakers that will produce destructive interference at a listener standing in front of them? The speed of sound is 338 m/s.
Physics
1 answer:
Annette [7]4 years ago
4 0

Answer:

1.21m

Explanation:

If two speakers are generating a frequency of 280Hz, the smallest separation distance between the speakers that will produce destructive interference at a listener standing in front of them is also known as the wavelength of the sound wave generated.

Using the expression;

Velocity v = frequency f × wavelength ¶

Given frequency = 280Hz, speed of sound v = 338m/s

Substituting this data's in the expression given to get the wavelength will give;

¶ = v/f

¶ = 338/280

¶ = 1.21m

The smallest separation between the speakers that will produce the interference is 1.21m

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Which tuning forks will give rise to a beat frequency of 20 Hz when sounded together with a 240 Hz tuning fork?
Lubov Fominskaja [6]

Use the concept of beat frequency to find the applicable final freqeuncy for 20Hz beat frequency.

Beat can be defined as 'the interference pattern between two sounds of slightly different frequencies0

The expression for beat frequency is given as

f_{beat} = |f_1-f_2|

Where,

f_2 = Final frequency

f_1 = Initial frequency

The beat frequency for us is 25Hz and the initial frequency is 240Hz, then

20= |f_2-240|

Being an absolute value, two values are possible, both in addition and subtraction:

f_2 = 240 \pm 20

The two possible values are

f_2 = 220Hz

f_2 = 260Hz

3 0
3 years ago
What is the magnitude of the momentum change of two gallons of water (inertia about 7.3 kg ) as it comes to a stop in a bathtub
aliya0001 [1]

We know that the change in momentum is equals to the product of force and time that is impulse (  F \times t). Therefore, we need to determine the value of that the water is in air by using the second equation of motion,

s=ut+\frac{1}{2} gt^2

Here, u is initial velocity which is zero.

s= \frac{1}{2} gt^2 \\\\ t = \sqrt{\frac{2s}{g} }.

Thus, impulse

= F \times \sqrt{\frac{2s}{g} }

From Newton`s second law,

F =mg

Therefore, impulse

= mg \times \sqrt{\frac{2s}{g} } = m \sqrt{2gs}

Given,  m = 7.3 kg and s = 2.0 m

Substituting these values, we get

Change in momentum = impulse  

= 7.3 \ kg \sqrt{2 \times 9.8 \ m/s^2 \times 2.0 \ m } = 45 .7 \ Ns.

8 0
3 years ago
In a pendulum system, when is it possible for the potential and kinetic energies both to be equal to zero
muminat
That's ONLY true when the pendulum is hanging
in the center position and not moving.
8 0
4 years ago
An object has a kinetic energy of 175 J and a momentum of magnitude 25.0 kg m/s. Find the
DedPeter [7]

Answer:14 m/s

Explanation:

Kinetic energy(ke)=175J

Momentum(M)=25kgm/s

Speed=v

Mass=m

Ke=(m x v x v)/2

175=(mv^2)/2

Cross multiply

175 x 2=mv^2

350=mv^2

Momentum=mass x velocity

25=mv

m=25/v

Substitute m=25/v in 350=mv^2

350=25/v x v^2

350=25v^2/v

v^2/v=v

350=25v

v=350/25

v=14 m/s

5 0
4 years ago
The figure shows three displacement vectors, which are
aleksley [76]

Answer:

the correct answer is D

Explanation:

In this exercise, the vectors are in the same west-east direction, so we can assume that the positive direction is east and perform the algebraic sum.

       R = δ + ε

where

       δ = 2.0 m

       ε = 7.0 m

the positive sign indicates that it is heading east

        R = 2.0 + 7.0

        R = 9.0 m

the direction is east

the correct answer is D

8 0
3 years ago
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