Question

Two speakers, one directly behind the other, are each generating a 280-Hz sound wave. What is the smallest separation distance between the speakers that will produce destructive interference at a listener standing in front of them? The speed of sound is 338 m/s.

Answer 1

Answer:

1.21m

Explanation:

If two speakers are generating a frequency of 280Hz, the smallest separation distance between the speakers that will produce destructive interference at a listener standing in front of them is also known as the wavelength of the sound wave generated.

Using the expression;

Velocity v = frequency f × wavelength ¶

Given frequency = 280Hz, speed of sound v = 338m/s

Substituting this data's in the expression given to get the wavelength will give;

¶ = v/f

¶ = 338/280

¶ = 1.21m

The smallest separation between the speakers that will produce the interference is 1.21m