Answer:
B = 0.8 T
Explanation:
It is given that,
Radius of circular loop, r = 0.75 m
Current in the loop, I = 3 A
The loop may be rotated about an axis that passes through the center and lies in the plane of the loop.
When the orientation of the normal to the loop with respect to the direction of the magnetic field is 25°, the torque on the coil is 1.8 Nm.
We need to find the magnitude of the uniform magnetic field exerting this torque on the loop. Torque acting on the loop is given by :
B is magnetic field
So, the magnitude of the uniform magnetic field exerting this torque on the loop is 0.8 T.
Answer:
Explanation:
Given
time taken 
Speed acquired in 2 sec 
Here initial velocity is zero 
acceleration is the rate of change of velocity in a given time
Distance travel in this time
where
s=displacement
u=initial velocity
a=acceleration
t=time
so Jet Plane travels a distance of 42 m in 2 s
Velocity 0.86m/s
0.13J
Explanation:
Given parameters:
Mass = 0.343kg
distance = 5m
time taken = 5.8s
Unknown:
Velocity of mass = ?
Kinetic energy = ?
Solution:
Velocity is the rate of change of displacement with time. It is a vector quantity that shows magnitude and direction.
Mathematically;
Velocity = 
Velocity = 
= 0.86m/s
Kinetic energy is the energy due to the motion of a body. It is expressed mathematically as:
Kinetic energy = 
m is the mass
v is the velocity
Kinetic energy = 
= 0.13J
learn more:
Kinetic energy brainly.com/question/6536722
#learnwithBrainly
You have to have electrons that are in the materials conduction band. Then you apply a voltage across the material.
B, air blowing from across the field is as a bullet fired from a rifle
