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jarptica [38.1K]
2 years ago
6

Two insulated current-carrying wires (wire 1 and wire 2) are bound together with wire ties to form a two-wire unit. The wires ar

e 2.83 m long and are stretched out horizontally parallel to each other. Wire 1 carries a current of I1 = 8.00 A and the other wire carries a current I2 in the opposite direction. The two-wire unit is placed in a uniform magnetic field of magnitude 0.400 T such that the angle between the direction of I1 and the magnetic field is 71.0°. While we don't know the current in wire 2, we do know that it is smaller than the current in wire 1. If the magnitude of the net force experienced by the two-wire unit is 3.50 N, determine the current in wire 2.
Physics
1 answer:
AysviL [449]2 years ago
7 0

Answer:

I'm not sure, My best friend knows, but I don't...

Explanation:

I'm sorry :)

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This B: False, because the definition is lacking.  

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3 years ago
1. What do you notice or wonder about ultrasound imaging? (black and white pictures)
a_sh-v [17]

Answer:

the shape how it involve into a picture

Explanation:

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3 years ago
A spring scale hung from the ceiling stretches by 5.2 cm when a 2.0 kg mass is hung from it. The 2.0 kg mass is removed and repl
pantera1 [17]
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8 0
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As a physics instructor hurries to the bus stop, her bus passes her, stops ahead, and begins loading passengers. She runs at 6.0
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v = 6 m/s

acceleration of the bus is given as

a = 2 m/s^2

acceleration of instructor with respect to bus is given as

a = -2 m/s^2

now the maximum distance that instructor will move with respect to bus is given as

v_f^2 - v_i^2 = 2 a d

0 - 6^2 = 2(-2)(d)

-36 = - 4 d

d = 9 m

so the position of the instructor with respect to door is exceed by

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7 0
3 years ago
Driving your Ferrari through the Italian countryside at a speedy 88 m/s, you approach an opera diva singing a high C (1,046 Hz).
MrRissso [65]

Answer:

You will hear the note E₆

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f' = \frac{v \pm v0 }{v \mp vs}*f

Where:

f = original frequency

f' = new frequency

v = velocity of the sound wave

v0 = your velocity

vs = velocity of the source, in this case, the source is the diva, we assume that she does not move, so vs = 0.

Replacing the values that we know in the equation we have:

f' = \frac{340 m/s + 88m/s}{340 m/s} *1,046 Hz = 1,316.73 Hz

This frequency is close to the note E₆ (1,318.5 Hz)

7 0
2 years ago
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